Volume

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    table 1 is 1 kg, the volume is 10 L and the density is 0.1 kg/L. The mass of table 2 is 2 kg, the volume is 10 L and the density is 0.2 kg/L. As shown, when the mass rose and the volume stayed the same the density increased. Table 10 shows an indirect relationship between density and volume. All of the blocks on this chart has the same mass, 5 kg. The red block volume’s 1.25 L and the density is 4 kg/L. The green block volume’s 2.5 L and the density is 2 kg/L. As shown when the volume of the block

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    Tidal Volume Lab Report

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    Results of the practical: What is tidal volume? The tidal volume is the normal rate of volume that moved into or out of the lungs during the process of breathing. The amount of oxygen we inhale and exhale can vary depending on the rate of breathing. The total average lung capacity of an adult is about 6 litres of air where only a small quantity is used during the breathing process. The rates of breathing and the respiratory process vary depending on the person and its physical conditions. The diet

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    Volume visualization is the technique of displaying two-dimensional projections of three-dimensional (volume) data. Volume rendering techniques of 3D data are classified as direct and indirect. Indirect volume rendering methods, such as Marching Cubes [1], extract intermediate geometric meshes of iso-surfaces from volume data and render them using surface rendering methods. Indirect methods are more suitable for applications where the visualization of surfaces is important. Direct Volume Rendering

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    Molar Volume Lab Report

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    Molar Volume Lab Report Objective: To find the molar volume of hydrogen gas at STP. Materials: Mg ribbon, thermometer, barometer, 6M HCL, eudiometer(Acid), 50 ml beaker, 400 ml beaker, cotton thread, base #7, pipet, ring stand, buret clamp, funnel, cork(hole through center vertically), cylinder full of water Procedure: The eudiometers was clamped onto the buret clamp on the ring stand. The mass of the Mg ribbon was recorded and was the bent to form a circle. A 15.0 cm long cotton thread was then

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    block number dimensions volume mass density 1 L=14.8cm w=8.6cm h=2.4cm 305.4 cm 125g 0.40g/cm 2 L=8.5cm w=5.5cm h=2.4cm 112.2 cm 46g 0.40g/cm 3 L=8.8 cm w=2.4cm h=2.3cm 33.7 cm 14g 0.41/cm 4 L=2.7cm w=2.4cm h=2.3cm 14.9 cm 6g 0.40/cm average 0.4025g/cm block number dimensions volume mass density 1 L=11.6cm w=4.8cm h=1.7cm 94.6cm 74g 0.78g/cm 2 L=8.6cm w=4cm h=1.7cm 161.68cm 45g 0.27g/cm 3 L=8.7cm w=2.8cm h=1.7cm 12.8cm 31g 2.42g/cm 4 L=2.4cm w=2.9cm h=1.6cm 11.13cm 8g 0.71g/cm average 108

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    Formula Volume Formula (cube 2 S.A. 6  s 3 V s  sphere 2 S.A. 4  r 4 3 3 V r   cylinder 2 S.A. 2 2     r Rh 2 V r h. Cube: s/6 Sphere: 0.333333r Cylinder: 6.283185h+6.283185r Volume to surface ratio: = s^3 / 6s^2 = s/6. Cube shaped sphere shaped cylinder shaped Volume 16 16 16 Surface area 38.097625 30.706532 35.207969 Volume/S.A Ratio .419973 .521061 .454442 S.A/Volume Ratio

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    The density of water is its mass divided by its volume. In this case, the mass of water was determined by subtracting the final mass of the glassware with water by the initial mass of the glassware without water. The volume was determined by observing closely which line (marked on the sides of each glassware) the water reached and reporting the most precise measurement. Based on the class data, the average densities of water and its standard deviations were: 50-mL beaker – avg: 0.90 g/mL, stand dev:

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    given unit volume. A physical property can be measured without changing the chemical identity of the substance. Since pure substances have unique density values, measuring the density of a substance can help identify that substance. Density is determined by dividing the mass of a substance by its volume. Density, volume, and mass have a clear relationship that can clearly be shown by the mathematical formula: Density= Mass/Volume In our experiment we used the determined mass and volume of the sample

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    [Type text] [Type text] [Type text] _An experiment on the effect of surface area to volume ratio on the rate of osmosis of Solanum tuberosum L._ BACKGROUND A cell needs to perform diffusion in order to survive. Substances, including water, ions, and molecules that are required for cellular activities, can enter and leave cells by a passive process such as diffusion. Diffusion is random movement of molecules in a net direction from a region of higher concentration to a region of lower concentration

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    Objective This experiment will involve measuring the volume and mass of a cylinder, a sphere and a wooden block. Based on the mass and volumes of these objects, the density of these objects can be calculated. The equation for the density of an object is density =mass/volume. In the density equation there is a direct proportional relationship between the mass of an object and its volume. For instance, if an object has its mass decreased, its volume will also decrease. The experiment used a Vernier

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