What is the Molar Mass of Mg(NO₃)₂?
Answer – The molar mass of Mg(NO₃)₂, or magnesium nitrate, is 148.3124 g/mol.
Explanation:
The molar mass of a compound is the mass of one mole of that compound in grams. In other words, it indicates how many grams of the compound are present in every mole of it. It is hence expressed in grams per mole.
A compound’s molar mass is arrived at by adding the atomic masses of each of its constituent atoms. And to go about the calculations for this, we follow a step-by-step approach:
- We begin by using the chemical formula of the compound to identify how many atoms of each element it contains.
- Then, we multiply the atomic mass of each element with its respective number of atoms in the compound. The atomic masses can be obtained from the periodic table.
- Finally, we sum up all the values obtained for the various elements to get the molar mass of the compound.
For radicals like NO₃ (nitrate), SO₄ (sulfate), CO₃ (carbonate), OH (hydroxide), etc., the number of atoms in a compound must be calculated carefully. This is especially true when the chemical formula indicates the presence of 2 or more such radicals, shown by parentheses – like for OH in Ca(OH)₂. This simply means that we need to multiply the subscript 2 outside the parentheses with the subscripts inside the parentheses to get the number of atoms. If there are no subscripts inside, we consider 1 as the default. Thus, there are 1 ✕ 2 oxygen atoms and 1 ✕ 2 hydrogen atoms in Ca(OH)₂.
Let us now use the above approach to calculate the molar mass of the given compound Mg(NO₃)₂.
1. First, we identify how many atoms of each element there are in the compound from the chemical formula:
1 Mg atom
1 ✕ 2 N atoms
3 ✕ 2 O atoms
2. Now, we use the periodic table to get the atomic masses of Mg, N, and O and multiply these values with their respective number of atoms in the compound.
From the periodic table, we get the atomic mass of Mg as 24.305 g/mol, atomic mass of N as 14.0067 g/mol, and atomic mass of O as 15.999 g/mol.
On multiplying the atomic masses with the number of atoms, we get:
1 Mg = 1 ✕ 24.305 = 24.305 g/mol
2 N = 2 ✕ 14.0067 = 28.0134 g/mol
6 O = 6 ✕ 15.999 = 95.994 g/mol
3. Finally, we add the obtained values to get the molar mass of Mg(NO₃)₂:
24.305 g/mol + 28.0134 g/mol + 95.994 g/mol = 148.3124 g/mol
Thus, the molar mass of Mg(NO₃)₂ is 148.3124 g/mol.
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