. An ideal gas with Cv = 1.62 kJ/kg-K and R = 273J/kg-K expands from 0.15m3 cubic meter) and 27 deg. C to 0.35 m3 (cubic meter) during an isobaric process vith p = 150kPa. Consider the process reversible nonflow, determine:
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- A piston/cylinder arrangement contains one mole of an ideal gas (the system) initially at 10.0 atm pressure and 300 K, as shown in the accompanying illustration. Neglecting the mass of the piston, neglecting friction, and assuming isothermal conditions throughout, the pin restraining the piston is removed. For the resulting process: (g = 9.807 m sR7) (a) What is qsyst if the mass of the weight is zero? (b) What is qsyst if the mass of the weight is 100 kg? (c) What is qsyst if the mass of the weight is 1017.4 kg?1 mol monoatomic ideal gas experienced an irreversible adiabatic process from state (P₁, T₁) to a final state (1atm, 273 K). AS is determined to be 20.9 J K-¹ mol-¹, and w=-1255J, C₁ = 3R/2, S (273K)= 188.3JK¯¹ mol-¹. Evaluate AU, AG of the process as well as the m initial state (P₁, T₁).The molar heat capacity (Cp (T)) for iron is given by the following Shomate equation, and P,m is valid between 298-700 K, 0.012643 Cp.m (T)=| 18.42+24.64T – 8.914T² +9.665T³ - J mol K- P,m Calculate AH when heating 1 g of Fe from 200-250°C.
- 9. L ks] 4.50 mol of N₂ gas (Cvm = 20.6 J mol-¹ K-¹) is enclosed in a piston-cylinder assembly (closed system) and undergoes the cycle depicted graphically below. Assuming N₂ behaves as an ideal gas, calculate q, w, AU and AH for each segment (in kJ). Label each segment with the type of process. Note: segment 2+3 follows the relationship PV = nRT. P (bar) 1.) 20.0 L 2.) 50.0 L 3.) 5.00 bar T = T₂ = T₂ V (L) 27. A 0.5 m3 rigid tank contains nitrogen gas at 600 kPa and 300 K. Now the gas is compressed isothermally to a volume of 0.1 m3. The work done on the gas during this compression process is: Oa) -720 kJ Ob) -175 kJ Oc) -483 kJ Od) -143 kJ Oe) None of aboveQui Air in a closed piston-cylinder arrangement is expanded from the initial pressure of 8.3 bar and initial volume of O.029 m to the final state of p2 2.2 bar. A polytropic relation of pV13 = constant was followed between pressure and volume for the process. The specific internal energy at the initial and final states are 156.5 and 101.5 kJ/kg, respectively. The mass of the air is 0.28 kg. Neglecting the effect of kinetic and potential energy, determine the heat transfer, inkJ.
- 1.0 mole of an ideal gas is initially at T1=298 and has volume of v1=2.0L. it is then reversibly expanded to V2=3.0L. assume Cp=5/2 R and Cv=3/2R. 1-calculate delta (T, H,U) and heat and work for both isothermal and adiabatic processes 2- calculate the initial and final pressure for isothermal and adiabtic processes.3. Heat capacities are usually given in terms of polynomial functions of temperature. The equation for the heat capacity of an ionic liquid is where T(R) and Cp (Btu Ibmol-1 R-1). Cp = 8.448 + 0.5757 × 10-2T+7.693 × 10-³ T log(0.325 T) (a) Determine the units of the constants (b) Develop an equation to calculate Cp in (Jxgmol-¹xK-1) as a function of Tin K. Express the coefficients in scientific notation and in four (4) significant figures.2.5 moles of an ideal gas at 300 ° K is supplied 1500 cal in two ways: A) At constant pressure. B) At constant volume. Calculate the final temperature, Q, W, A H, A U and A S, for processes A) and B). DATA: Čp = 5 cal / mol-K at all temperatures. %3D
- A gas in the initial state of p1 = 75 psia and V1 = 5 ft.3 undergoes a process to p2 = 25 psia and V2 = 9.68 ft., during which the enthalpy decreases 62 BTU. The %3D specific heat at constant volume is c, = 0.754 BTU/lb.°R. Determine (a) the change of internal energy, (b) the specific heat at constant pressure, (c) the gas constant R.°Thermo- Problem 4.23 At 298 K. AH; 131.28 kJ-mol for the reaction -1 with Cp.-8.53, 33.58, 29.12, and 28.82 J K mol for graphite, H₂O(g). CO(g), and H₂(g), respectively Part A Calculate AH; at 210 *C from this information. Assume that the heat capacities are independent of temperature. Express your answer to five significant figures and include the appropriate units. ΔΗ: (210 °C) - Submit Provide Feedback HÅ Value Request Answer Units C(graphite) + H₂O(g) → CO(g) + H₂(g)The gas A(g) (1 mole) undergoes a two-step process one after another as described below :i) The gas is expanded at 25°C and from 1 bar pressure against a constant pressure of 0.2 bar and the final volume of the gas is the twice the initial volume.ii) The gas is cooled down to -25°C at constant volume.Cv,m = 3/2 RCalculate ΔU, ΔH, q and w for the each step and for the entire process