. Consider the same case as discussed in question 4. Calcúlate the value of x hålfway bétweet x Calculate U+U, = %kx² -mgx for that point. How does it compare with the values calculated in question 4? Explain the reason for this result.

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Follow-up Questions
4. Instead of comparing changes in energy, compare the total energy at each point. Consider the first
case of the 0.500 kg mass falling from x;=0.250 m to the value of x2 determined for that case. Calculate
the sum Uk + U, at x, as %kx;? – mgx1. Now calculate that sum at x2 as 1/2kx22 – mgx2. Compare the two
and comment on the significance of the comparison.
MASS (M) 0.5kg
X, - 0.250m
÷ hy'.을 (15XY1)- 2-45-1.225J
2
• 1.225 +0
mgx, 0.5 (9.8X 0.250) - 1,225J
V 179X, 2 Y4.8*0.250
: 19.9·2-21 mS
•1. 225J
WE CAN CONCIVDE HERE THAT ENERGY IS CONSERVED
IT CAN BE CONVEETEV FFOM OME FOEM TO AMO THER. HEVE,
yoEMAL EM FGY IS OMETE T KIMT EME6Y-
5. Consider the same case as discussed in question 4. Calcülate the value of x halfway between x
Calculate U+U, = ¼kx² –mgx for that point. How does it compare with the values calculated in
question 4? Explain the reason for this result.
Transcribed Image Text:Follow-up Questions 4. Instead of comparing changes in energy, compare the total energy at each point. Consider the first case of the 0.500 kg mass falling from x;=0.250 m to the value of x2 determined for that case. Calculate the sum Uk + U, at x, as %kx;? – mgx1. Now calculate that sum at x2 as 1/2kx22 – mgx2. Compare the two and comment on the significance of the comparison. MASS (M) 0.5kg X, - 0.250m ÷ hy'.을 (15XY1)- 2-45-1.225J 2 • 1.225 +0 mgx, 0.5 (9.8X 0.250) - 1,225J V 179X, 2 Y4.8*0.250 : 19.9·2-21 mS •1. 225J WE CAN CONCIVDE HERE THAT ENERGY IS CONSERVED IT CAN BE CONVEETEV FFOM OME FOEM TO AMO THER. HEVE, yoEMAL EM FGY IS OMETE T KIMT EME6Y- 5. Consider the same case as discussed in question 4. Calcülate the value of x halfway between x Calculate U+U, = ¼kx² –mgx for that point. How does it compare with the values calculated in question 4? Explain the reason for this result.
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