000A ... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same length L, of different currents ii and i2, and separated by a distance d. Using Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other of magnitude Ho ii2L F = (6.127) 27 d Using the right-hand-rules for the magnetic force and the magnetic field of a current-carrying wire, explain why this force is attractive for parallel currents and repulsive for antiparallel currents26.
000A ... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same length L, of different currents ii and i2, and separated by a distance d. Using Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other of magnitude Ho ii2L F = (6.127) 27 d Using the right-hand-rules for the magnetic force and the magnetic field of a current-carrying wire, explain why this force is attractive for parallel currents and repulsive for antiparallel currents26.
Chapter7: Electricity
Section: Chapter Questions
Problem 27P: . The generator at a large power plant has an output of 1,000,000 kW at 24,000 V. (a) If it were a...
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6.30 only
![6.33 In Figure P.6.4, VB = 12.0 V, R1 = 100.0 N, R2 = 55.0 N, R3 = 75.0 N,
concentric (i.e., same-center) cylinders. If a current of 55.0 mA is placed through
80 turns. You place the 5.0-cm coil inside the 12.0-cm coil, such that they form
the outer coil, how much current must be created in the inner coil such that the
RONICS
283
6.10. PROBLEMS TARD
... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same
length L, of different currents i and i2, and separated by a distance d. Using
Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other
of magnitude
Ho ii2 L
27 d
F =
(6.127)
Using the right-hand-rules for the magnetic force and the magnetic field of a
current-carrying wire, explain why this force is attractive for parallel currents
and repulsive for antiparallel currents26.
* 6.31 What current is required to create a magnetic field of 1.00 T in a 100-turn
solenoid of length 5.0 m with air (K, 1) in the center?
.. 6.32 You have two coils of wire; the first has a radius of 12.0 cm, a lenøơth of
1.0 m, and 50 turns: the second has a radius of 5.0 cm, a length of 1.0 m and
magnetic field at the center of the inner coil is zero?
R1
R2
VB
R4
6.4. Figur
ch resistor?
urr
and R4
= 15.0 O
hau](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2e6bca0-5751-4e3b-9150-515606817feb%2F95376b5c-2568-429b-9c6e-8bf6dc3778ea%2Fl4y6ts9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6.33 In Figure P.6.4, VB = 12.0 V, R1 = 100.0 N, R2 = 55.0 N, R3 = 75.0 N,
concentric (i.e., same-center) cylinders. If a current of 55.0 mA is placed through
80 turns. You place the 5.0-cm coil inside the 12.0-cm coil, such that they form
the outer coil, how much current must be created in the inner coil such that the
RONICS
283
6.10. PROBLEMS TARD
... 6.30 Consider two wires parallel to each other, as in Figure P.6.3, of the same
length L, of different currents i and i2, and separated by a distance d. Using
Eqs. (6.15), (6.26), and (6.27), show that these wires exert a force on each other
of magnitude
Ho ii2 L
27 d
F =
(6.127)
Using the right-hand-rules for the magnetic force and the magnetic field of a
current-carrying wire, explain why this force is attractive for parallel currents
and repulsive for antiparallel currents26.
* 6.31 What current is required to create a magnetic field of 1.00 T in a 100-turn
solenoid of length 5.0 m with air (K, 1) in the center?
.. 6.32 You have two coils of wire; the first has a radius of 12.0 cm, a lenøơth of
1.0 m, and 50 turns: the second has a radius of 5.0 cm, a length of 1.0 m and
magnetic field at the center of the inner coil is zero?
R1
R2
VB
R4
6.4. Figur
ch resistor?
urr
and R4
= 15.0 O
hau
![Figure P.6.3. Figure for Problem 4.30.
Figure P.6.2. Figure for Problem 4,28
wire 2
wire 1
and
d
of 50
6.
and
..
6.3
26
Ca](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2e6bca0-5751-4e3b-9150-515606817feb%2F95376b5c-2568-429b-9c6e-8bf6dc3778ea%2Foew7fsf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Figure P.6.3. Figure for Problem 4.30.
Figure P.6.2. Figure for Problem 4,28
wire 2
wire 1
and
d
of 50
6.
and
..
6.3
26
Ca
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