(1) Mass of KHP (g) 0.6364 g (2) Moles of KHP Convert to moles (M.W. 204.22 g/mole) (3) Initial volume of burette (mL) 0.00 mL (4) Final volume of burette (mL) 31.10 mL (5) Total volume used (mL) (4) – (3) (6) Total volume used (L) Convert (5) to Liters (7) Moles of NaOH Moles of base = moles of KHP (2) at neutralization point (8) Molarity of Base (M)

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Acid-base titration: Determine the concentration of a NaOH solution. Solve2,6,7,8. 

Trial 1
(1) Mass of KHP (g) 0.6364 g
(2) Moles of KHP
Convert to moles
(M.W. 204.22 g/mole)
(3) Initial volume of
burette (mL)
0.00 mL
(4) Final volume of
burette (mL)
31.10 mL
(5) Total volume used
(mL)
(4) – (3)
(6) Total volume used
(L)
Convert (5) to Liters
(7) Moles of NaOH
Moles of base =
moles of KHP (2)
at neutralization point
(8) Molarity of Base
(M)
Transcribed Image Text:Trial 1 (1) Mass of KHP (g) 0.6364 g (2) Moles of KHP Convert to moles (M.W. 204.22 g/mole) (3) Initial volume of burette (mL) 0.00 mL (4) Final volume of burette (mL) 31.10 mL (5) Total volume used (mL) (4) – (3) (6) Total volume used (L) Convert (5) to Liters (7) Moles of NaOH Moles of base = moles of KHP (2) at neutralization point (8) Molarity of Base (M)
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