1. Given the following definition of fun1, what will be output by the call fun1 (4)?void fun1(int n) {int i = 0;if (n > 1) {O O* *** *★*** * *******fun1(n-1);}for (i = 0; i A member variable declared in the private section of a base class can be directly accessed within a member function of a derived class that inherits from this base class.TrueFalse

We have toi explain that what is the output of the function when we call fun(4). void fun1(int n)…

Answered: 1. Given the following dennition of…

1. Given the following dennition of fun, what will be output by the call funi (4): void fun1(int n) { int i=0; * * } **** * if (n> 1) { * fun1(n-1); + } for (i = 0; i

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter10: Introduction To Inheritance

Section: Chapter Questions

Problem 12RQ

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Question

1. Given the following definition of fun1, what will be output by the call fun1 (4)?
void fun1(int n) {
int i = 0;
if (n > 1) {
O O
* *
*
* *
★
*
*
* * *
*
*
*
*
*
*
fun1(n-1);
}
for (i = 0; i<n; i++) {
cout << "*";
}
cout << endl;
}
*
* *
* *
* * * *
* *
* *
* *
* * *
* * *

A member variable declared in the private section of a base class can be directly accessed within a member function of a derived class that inherits from this base class.
True
False

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