2. A string with a length of 2.00 meters is configured as shown below. The linear mass density of the string is 20.0 grams/meter. The suspended mass is initially at 5.00 kg. -2 meters- Oscillating Rod a. What frequency should the oscillating rod vibrate at in order to produce a n=7 standing wave on the string? 86.62 fz = 7 7 2 (2m) Suspended mass (49N) 0.02 kg/m b. If the mass attached varies with time and obeys the equation m(t) = 0.0012 + 5.00, at what time will the next standing wave be produced (state it's harmonic number as well).

University Physics Volume 1
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Chapter16: Waves
Section: Chapter Questions
Problem 105P: A cable with a linear density of =0.2 kg/m is hung from telephone poles. The tension in the cable is...
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Solve part b
0.02 kg/m
2. A string with a length of 2.00 meters is configured as shown below. The linear mass density of
the string is 20.0 grams/meter. The suspended mass is initially at 5.00 kg.
-2 meters-
Oscillating
Rod
a. What frequency should the oscillating rod vibrate at in order to produce a n=7 standing wave
on the string?
(49 N)
0.02kg/m
다
fz=
=
Suspended mass
7
2 (2m)
=
86.62 Hz
b. If the mass attached varies with time and obeys the equation m(t) = 0.0012 + 5.00, at what
time will the next standing wave be produced (state it's harmonic number as well).
***
Transcribed Image Text:0.02 kg/m 2. A string with a length of 2.00 meters is configured as shown below. The linear mass density of the string is 20.0 grams/meter. The suspended mass is initially at 5.00 kg. -2 meters- Oscillating Rod a. What frequency should the oscillating rod vibrate at in order to produce a n=7 standing wave on the string? (49 N) 0.02kg/m 다 fz= = Suspended mass 7 2 (2m) = 86.62 Hz b. If the mass attached varies with time and obeys the equation m(t) = 0.0012 + 5.00, at what time will the next standing wave be produced (state it's harmonic number as well). ***
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