2.2-lb steel tape is 99.98 ft long at 68° F v
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![A 2.2-lb steel tape is 99.98 ft long at 68° F while supported for its full length with a 10-lb pull. It has
a cross-sectional area of 0.005 sq in. and E= 29 x 106 psi. The tape held horizontally, supported at its
ends only, and pulled with a force of 25-lb. The distance measured is 3500.50 ft under the
temperature of 83° F. Determine the correct distance (Consider Temperature, Tension and Sag
Correction ONLY). You must provide solutions to support your answer.
Formula
Ctemp = 0.00000645 x (T-68°F) x L, Ctension = (P-Ps)L/AE, Csag = - W² x L / (24 x P²)
(Cslope = -(S)² / (2 x L), )
where, T = temperature, L = Tape length, S = slope, W = weight of tape, P = applied tension, P, =
standard tension, A = cross-section area](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa06fb91f-1445-4bd6-b9dd-268642fc0d22%2F5ef0e5f5-bef9-44aa-a904-73a31e1784b2%2Fe0qwu5p.jpeg&w=3840&q=75)
Transcribed Image Text:A 2.2-lb steel tape is 99.98 ft long at 68° F while supported for its full length with a 10-lb pull. It has
a cross-sectional area of 0.005 sq in. and E= 29 x 106 psi. The tape held horizontally, supported at its
ends only, and pulled with a force of 25-lb. The distance measured is 3500.50 ft under the
temperature of 83° F. Determine the correct distance (Consider Temperature, Tension and Sag
Correction ONLY). You must provide solutions to support your answer.
Formula
Ctemp = 0.00000645 x (T-68°F) x L, Ctension = (P-Ps)L/AE, Csag = - W² x L / (24 x P²)
(Cslope = -(S)² / (2 x L), )
where, T = temperature, L = Tape length, S = slope, W = weight of tape, P = applied tension, P, =
standard tension, A = cross-section area
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