2N2 (g) + 502 (g) → 2N2O5 () + 86.4 Joule T= 200°C P = 2 atm increase in concentration of O2 A. Backward B. No shift addition of Cao to remove N205 C. Forward increase in concentration of N205 decrease in the volume increase in the concentration of N2 decrease in the pressure change in temperature to 350°C addition of Ne, an inert gas addition of H2 to neutralize N2 B. v addition of a positive catalyst
2N2 (g) + 502 (g) → 2N2O5 () + 86.4 Joule T= 200°C P = 2 atm increase in concentration of O2 A. Backward B. No shift addition of Cao to remove N205 C. Forward increase in concentration of N205 decrease in the volume increase in the concentration of N2 decrease in the pressure change in temperature to 350°C addition of Ne, an inert gas addition of H2 to neutralize N2 B. v addition of a positive catalyst
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Chapter13: Fundamental Equilibrium Concepts
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![2N2 (g) + 502 (g) → 2N2O5 (g) + 86.4 Joule
T= 200°C P= 2 atm
v increase in concentration of 02
A. Backward
addition of Cao to remove N205
B. No shift
v increase in concentration of N205
C. Forward
decrease in the volume
increase in the concentration of N2
v decrease in the pressure
v change in temperature to 350°C
addition of Ne, an inert gas
v addition of H2 to neutralize N2
B. v addition of a positive catalyst](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3968424b-c029-4a4c-8be8-ab35f77d9ec2%2Fa4c9b9f7-5988-4ad3-ad52-7c34498866d0%2F5gkcc9_processed.png&w=3840&q=75)
Transcribed Image Text:2N2 (g) + 502 (g) → 2N2O5 (g) + 86.4 Joule
T= 200°C P= 2 atm
v increase in concentration of 02
A. Backward
addition of Cao to remove N205
B. No shift
v increase in concentration of N205
C. Forward
decrease in the volume
increase in the concentration of N2
v decrease in the pressure
v change in temperature to 350°C
addition of Ne, an inert gas
v addition of H2 to neutralize N2
B. v addition of a positive catalyst
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