College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter5: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 4CC
Related questions
Topic Video
Question
Sec10.3: #29 only
![29–38 1 Linear Systems with One Solution The system of lin-
ear equations has a unique solution. Find the solution using
Gaussian elimination or Gauss-Jordan elimination.
2y + z =
1
x + y + 6z = 3
X
-
- 29.
y + 2z = 5
30.
x + y + 3z = 3
x + y + 3z = 8
x + 2y + 4z = 7
x +
z = 2
х+ у+
z =
4
31.
2х -
Зу + 2z — 4
32.
-x + 2y + 3z = 17
(4х + у — 3z 3D 1
2х -
y
= -7
x + 2y – z = -2
- 33.
2y + z = 4
+ z =
34.
x + y
4
(2х — у — z 3D — 3
(3х + Зу — z 3D 10
X1 + 2x2 ·
2x1
7
X3
X2
35. {2х]
-2
36.
2x1
6.
X3
2x2 + 4x3
X3
X2
(3x + 5х, + 2х;
= 22
(3x1
11
2х — Зу —
z = 13
10х + 10y — 20z
60
|
37.
-x + 2y – 5z = 6
38.
15х + 20у + 30z
25
%3D
5х -
y
z = 49
- 5x + 30y
10z
45
-
+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05eff97e-864f-43d9-95b7-8e6395ef9971%2Fb5625c9c-987b-4e84-8c5b-027d2da13238%2Fmzhs4gm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:29–38 1 Linear Systems with One Solution The system of lin-
ear equations has a unique solution. Find the solution using
Gaussian elimination or Gauss-Jordan elimination.
2y + z =
1
x + y + 6z = 3
X
-
- 29.
y + 2z = 5
30.
x + y + 3z = 3
x + y + 3z = 8
x + 2y + 4z = 7
x +
z = 2
х+ у+
z =
4
31.
2х -
Зу + 2z — 4
32.
-x + 2y + 3z = 17
(4х + у — 3z 3D 1
2х -
y
= -7
x + 2y – z = -2
- 33.
2y + z = 4
+ z =
34.
x + y
4
(2х — у — z 3D — 3
(3х + Зу — z 3D 10
X1 + 2x2 ·
2x1
7
X3
X2
35. {2х]
-2
36.
2x1
6.
X3
2x2 + 4x3
X3
X2
(3x + 5х, + 2х;
= 22
(3x1
11
2х — Зу —
z = 13
10х + 10y — 20z
60
|
37.
-x + 2y – 5z = 6
38.
15х + 20у + 30z
25
%3D
5х -
y
z = 49
- 5x + 30y
10z
45
-
+
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