4, xydx (x² + 3y²) dy = 0 Homogeneous, 2nd degree Let x = vy dx= vdy + ydv Substitute. vy² (vdy+ydv)-(v²y2 + 3y2) dy=0 vy² (vdy + ydv)- y² (v²+3) dy = 0. divide by y2, v²dy + vydv (v²+3) dy = 0 vydv - 3dy = 0 divide by y. vdv - but : 3 dy y fvdv - 3 fo ²-3 ln y = -3 Inc v²-6lny = -6 Inc y² = 6lny - 6 Inc v² = = 0 6 In v = ²=6 = 6 In y/c x² = 6y² In y/c ans.
4, xydx (x² + 3y²) dy = 0 Homogeneous, 2nd degree Let x = vy dx= vdy + ydv Substitute. vy² (vdy+ydv)-(v²y2 + 3y2) dy=0 vy² (vdy + ydv)- y² (v²+3) dy = 0. divide by y2, v²dy + vydv (v²+3) dy = 0 vydv - 3dy = 0 divide by y. vdv - but : 3 dy y fvdv - 3 fo ²-3 ln y = -3 Inc v²-6lny = -6 Inc y² = 6lny - 6 Inc v² = = 0 6 In v = ²=6 = 6 In y/c x² = 6y² In y/c ans.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 31E
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