4. Oil at a rate of 13ft/s is flowing steadily from tank A to tank B through 40 pipe (The ID of 3-in schedule 40 pipe is 3.068 in, the absolute roughness is 0.0018 in) The oil has a density of 62.3 lbm/ft³ and a viscosity of 50 cP. The levels of the free surfaces are the same in both tanks. Tank B is vented to the atmosphere. Neglecting the expansion and contraction losses, What is the gauge pressure in Tank A required to produce this flow rate? Tank A L=1000 ft Vent Tank B
4. Oil at a rate of 13ft/s is flowing steadily from tank A to tank B through 40 pipe (The ID of 3-in schedule 40 pipe is 3.068 in, the absolute roughness is 0.0018 in) The oil has a density of 62.3 lbm/ft³ and a viscosity of 50 cP. The levels of the free surfaces are the same in both tanks. Tank B is vented to the atmosphere. Neglecting the expansion and contraction losses, What is the gauge pressure in Tank A required to produce this flow rate? Tank A L=1000 ft Vent Tank B
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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i have calculate friction and reynolds but dont know how to calc the guage pressure needed
Transcribed Image Text:4. Oil at a rate of 13ft/s is flowing steadily from tank A to tank B through 1000 ft of 3-in schedule
40 pipe (The ID of 3-in schedule 40 pipe is 3.068 in, the absolute roughness is 0.0018 in) The oil
has a density of 62.3 lbm/ft3 and a viscosity of 50 cP. The levels of the free surfaces are the same
in both tanks. Tank B is vented to the atmosphere. Neglecting the expansion and contraction losses,
What is the gauge pressure in Tank A required to produce this flow rate?
Tank A
L=1000 ft
2
Vent
Tank B
Transcribed Image Text:f = 0.00135 1+20,000
R₂ =
€ 106
1+ (20,000 + R
pDV
μ
= 0.000888
(3.068in *
= 0.00135[1 +20,000 *
1ft)(13ft)(62.3 lbm.
ft3)
12in
50 CP 6.72 * 10-4
lbm
ft.s
= 6162.63
0.0018 inv
3.068 in
+
106
6162.63
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