4.10 LAB: Exception handling to detect input string vs. integer The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 # Split input into 2 parts: name and age parts = input().split() name = parts[0] while name != '-1': try: age = int(parts[1]) + 1 except: age - 1 print('{} {}'.format(name, age)) parts = input().split() name = parts[0] Traceback Total score: 0 / 10 Only show failing tests Download this submission 1: Compare outputkeyboard_arrow_up 0 / 1 Output differs. See highlights below. Input Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 Your output Lee 19 Lua 22 Mary 22 Stu 34 Expected output Lee 19 Lua 22 Mary 0 Stu 34 2: Compare outputkeyboard_arrow_up 0 / 3 Output differs. See highlights below. Input Laura 63 Vaishnavi 24 Sarah Sims 33 -1 Your output Laura 64 Vaishnavi 25 Sarah 25 Expected output Laura 64 Vaishnavi 25 Sarah 0 3: Compare outputkeyboard_arrow_up 0 / 3 Output differs. See highlights below. Input Huw 29 Jaspar 49 Melina Lynn 32 Quinta 13 Mina Ny 38 Hanna 28 -1 Your output Huw 30 Jaspar 50 Melina 50 Quinta 14 Mina 14 Hanna 29 Expected output Huw 30 Jaspar 50 Melina 0 Quinta 14 Mina 0 Hanna 29 4: Compare outputkeyboard_arrow_up 0 / 3 Traceback (most recent call last): File "main.py", line 6, in age = int(parts[1]) + 1 ValueError: invalid literal for int() with base 10: 'Jean' During handling of the above exception, another exception occurred: Traceback (most recent call last): File "main.py", line 8, in age - 1 NameError: name 'age' is not defined Input Laura Jean 17 Christine 55 Felicia 31 Kofi Drew 39 Margaux 98 -1 Your output Your program produced no output Expected output Laura 0 Christine 56 Felicia 32 Kofi 0 Margaux 99

4.10 LAB: Exception handling to detect input string vs. integer The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 # Split input into 2 parts: name and age parts = input().split() name = parts[0] while name != '-1': try: age = int(parts[1]) + 1 except: age - 1 print('{} {}'.format(name, age)) parts = input().split() name = parts[0] Traceback Total score: 0 / 10 Only show failing tests Download this submission 1: Compare outputkeyboard_arrow_up 0 / 1 Output differs. See highlights below. Input Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 Your output Lee 19 Lua 22 Mary 22 Stu 34 Expected output Lee 19 Lua 22 Mary 0 Stu 34 2: Compare outputkeyboard_arrow_up 0 / 3 Output differs. See highlights below. Input Laura 63 Vaishnavi 24 Sarah Sims 33 -1 Your output Laura 64 Vaishnavi 25 Sarah 25 Expected output Laura 64 Vaishnavi 25 Sarah 0 3: Compare outputkeyboard_arrow_up 0 / 3 Output differs. See highlights below. Input Huw 29 Jaspar 49 Melina Lynn 32 Quinta 13 Mina Ny 38 Hanna 28 -1 Your output Huw 30 Jaspar 50 Melina 50 Quinta 14 Mina 14 Hanna 29 Expected output Huw 30 Jaspar 50 Melina 0 Quinta 14 Mina 0 Hanna 29 4: Compare outputkeyboard_arrow_up 0 / 3 Traceback (most recent call last): File "main.py", line 6, in age = int(parts[1]) + 1 ValueError: invalid literal for int() with base 10: 'Jean' During handling of the above exception, another exception occurred: Traceback (most recent call last): File "main.py", line 8, in age - 1 NameError: name 'age' is not defined Input Laura Jean 17 Christine 55 Felicia 31 Kofi Drew 39 Margaux 98 -1 Your output Your program produced no output Expected output Laura 0 Christine 56 Felicia 32 Kofi 0 Margaux 99

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter14: Exception Handling

Section: Chapter Questions

Problem 22SA

See similar textbooks

4.10 LAB: Exception handling to detect input string vs. integer

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age.

Ex: If the input is:

Lee 18 Lua 21 Mary Beth 19 Stu 33 -1

then the output is:

Lee 19 Lua 22 Mary 0 Stu 34

# Split input into 2 parts: name and age
parts = input().split()
name = parts[0]
while name != '-1':
try:
age = int(parts[1]) + 1
except:
age - 1
print('{} {}'.format(name, age))

parts = input().split()
name = parts[0]

Traceback

Total score: 0 / 10

Only show failing tests

Download this submission

1: Compare outputkeyboard_arrow_up

0 / 1

Output differs. See highlights below.

Input

Lee 18 Lua 21 Mary Beth 19 Stu 33 -1

Your output

Lee 19 Lua 22 Mary 22 Stu 34

Expected output

Lee 19 Lua 22 Mary 0 Stu 34

2: Compare outputkeyboard_arrow_up

0 / 3

Output differs. See highlights below.

Input

Laura 63 Vaishnavi 24 Sarah Sims 33 -1

Your output

Laura 64 Vaishnavi 25 Sarah 25

Expected output

Laura 64 Vaishnavi 25 Sarah 0

3: Compare outputkeyboard_arrow_up

0 / 3

Output differs. See highlights below.

Input

Huw 29 Jaspar 49 Melina Lynn 32 Quinta 13 Mina Ny 38 Hanna 28 -1

Your output

Huw 30 Jaspar 50 Melina 50 Quinta 14 Mina 14 Hanna 29

Expected output

Huw 30 Jaspar 50 Melina 0 Quinta 14 Mina 0 Hanna 29

4: Compare outputkeyboard_arrow_up

0 / 3

Traceback (most recent call last): File "main.py", line 6, in <module> age = int(parts[1]) + 1 ValueError: invalid literal for int() with base 10: 'Jean' During handling of the above exception, another exception occurred: Traceback (most recent call last): File "main.py", line 8, in <module> age - 1 NameError: name 'age' is not defined

Input

Laura Jean 17 Christine 55 Felicia 31 Kofi Drew 39 Margaux 98 -1

Your output

Your program produced no output

Expected output

Laura 0 Christine 56 Felicia 32 Kofi 0 Margaux 99

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main.py
Load default template...
1 # Split input into 2 parts: name and age
2 parts
input().split()
3 name parts[0]
4 while name != '-1':
5
try:
6
age int (parts[1]) + 1
7
except:
8
age 1
9
print('{} {}'. format (name, age))
parts = input().split()
name parts[0]
Submit mode
Run your program as often as you'd like, before submitting for grading. Below, type any needed
input values in the first box, then click Run program and observe the program's output in the
second box.
Input (from above)
main.py
(Your program)
Output (shown below)
10
11
12
13
14
Develop mode
Enter program input (optional)
Lee 18
Lua 21
Run program
b Success Confirmation of Questic X
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6/21/2022

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