9. Calculate AH for the reaction 4NH3 (g) + 502 (g) → 4NO (g) + 6H20 (g), from the following data. a. N2 (g) + O2 (g) → 2 NO (g) b. N2 (g) + 3 H2 (g) → 2 NH3 (g) c. 2 H2 (g) + 02 (g) → 2 H20 (g) AH = -180. 5 kJ AH =-91. 8 kJ AH = -483. 6 kJ

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter12: The Solid State
Section12.3: Bonding In Ionic Compounds: Lattice Energy
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9. Calculate AH for the reaction 4NH3 (g) + 502 (g) → 4NO (g) + 6H20 (g), from the following
data.
a. N2 (g) + O2 (g) → 2 NO (g)
b. N2 (g) + 3 H2 (g) → 2 NH3 (g)
c. 2 H2 (g) + 02 (g) → 2 H20 (g)
AH = -180. 5 kJ
AH =-91. 8 kJ
AH = -483. 6 kJ
Transcribed Image Text:9. Calculate AH for the reaction 4NH3 (g) + 502 (g) → 4NO (g) + 6H20 (g), from the following data. a. N2 (g) + O2 (g) → 2 NO (g) b. N2 (g) + 3 H2 (g) → 2 NH3 (g) c. 2 H2 (g) + 02 (g) → 2 H20 (g) AH = -180. 5 kJ AH =-91. 8 kJ AH = -483. 6 kJ
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