A 0.100 L solution is prepared with initial concentrations of 4.0 × 10−3 M iodine I2 , 8.0×10−3 M iodide I– , and 5.0×10−3 M ascorbic acid C6H8O6 . After the second reaction goes to completion, what will the molar concentrations of iodide and ascorbic acid in the solution be?

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2I– (aq) + H2O2 (aq) + 2H3O + (aq) → I2 (aq) + 4H2O (l) (slow)

C6H8O6 (aq) + 2H2O (l) + I2 (aq) → C6H6O6 (aq) + 2H3O + (aq) + 2I– (aq) (very fast)

I2 (aq) + I– (aq) ⇌ I3- (aq)

I3- (aq) + starch → blue I3- · starch complex (aq) (fast)

A 0.100 L solution is prepared with initial concentrations of 4.0 × 10−3 M iodine I2 , 8.0×10−3 M iodide I– , and 5.0×10−3 M ascorbic acid C6H8O6 . After the second reaction goes to completion, what will the molar concentrations of iodide and ascorbic acid in the solution be?

Expert Solution
Step 1

Volume of Solution = 0.100 L

                   [I2]initial = 4.0 * 10-3 M

                   [I-]initial = 8.0 * 10-3 M

         [C6H8O6]initial = 5.0 * 10-3M

         I2 (aq) + I-(aq)--------> I3- (aq)

         Therefore, I3- formed = 4.0 * 10-3M

         (0.004 M iodine combines with 0.004 moles iodide and form 0.004 moles triiodide ion)        

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