A 100-g block hangs from a spring with k = 5.00 N / m. At t = 0, the block is 20 cm below the equilibrium position and moving upward with a velocity of 20 cm / s. Based on this information, calculate the following:

Q: Compute the work required to stretch a spring from 4 to 12 cm past equilibrium, assuming that the…

A: Given: The spring constant is 180 kg/s2. The stretching of the spring from 4 cm to 12 c.

Q: A vertical spring with elastic constant 95 N/m is compressed by 25 cm, and an object of mass 350 g…

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Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 435 N/m as shown in the…

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Q: As shown in the figure below, a box of mass m = 8.00 kg is sliding across a horizontal frictionless…

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Q: How far a spring extended if it has 2.5J of elastic potential energy and its spring- constant is…

A: The formula of the elastic potential energy of a spring is  U=0.5 K x2 where, K is the spring…

Q: A 3.49-kg box placed against a horizontal spring with a force constant ofk= 228.7 N/m compresses the…

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Q: As seen in Fig. 1, a 5.00 kg mass starts from rest at the top of a frictionless incline at heighty0=…

A: Work done by gravitational force will be = mgh Work = 5 x 9.8 x 3 = 147 J  Using Work energy…

Q: A block of mass 2 kg is moving to the right with velocity V= 25 m/s. The block then compresses the…

A: Apply principle of conservation of energy 12mv2=12k∆x2mv2=k∆x2k=mv2∆x2  =2 kg25 ms20.5 m2   =5000 Nm

Q: A spring has an elastic potential energy of 115J when it is compressed 0.20m. what is the spring…

A: Spring is a mechanical device that always stores some potential energy when it is compressed. This…

Q: A block whose mass is 5.7 kg slides on horizontal frictionless table top with a constant speed of 5…

A: Given values: Mass, m=5.7 kg Speed, v=5 m/s Spring constant, K=1282.5 N/m

Q: In designing a spring loaded cannon, determine the spring constant required to launch a 1.0 kg ball…

A: Given data: Displacement of the ball x=5 cm =0.05m Mass of the ball m=1.0 kg Initial speed v=1.2 m/s

Q: A mass m = 16 kg rests on a frictionless table and accelerated by a spring with spring constant k =…

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Q: A box is pressed against a horizontal spring, compressing the spring from its relaxed length. The…

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Q: A 2.75 kg block on a horizontal floor is attached to a horizontal spring that is initially…

A: From conservation of energy,

Q: The horizontal surface on which a block slides is frictionless. The speed of the block is 6.0 m / s…

A: Here, ∆K=-UsKf-Ki=Ui-Uf      (Ui=0)Kf=Ki-Uf=12mvi2-12kxf2

Q: A block of mass 1.6 kg is held against a horizontal spring so that the spring is compressed 17 cm.…

A: The normal reaction acting on the block is: Therefore, the frictional force acting on the block is:…

Q: A 1500-kg car moving at 25 m/s hits an initially uncompressed horizontal ideal spring with spring…

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Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 590 N/m as shown in the…

A: The energy stored in spring will be transformed into the kinetic energy of the block when it reaches…

Q: A 0.500-kg cart connected to a light spring for which the force constant is 23.5 N/m oscillates on a…

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Q: The cable of the 1800 kg elevator cab snaps when the cab is at rest at the first floor, where the…

A: Since there are multiple sub-parts posted, we will answer the first three sub-parts for you. If you…

Q: A small block of mass M = 150 g is placed on top of a larger block of mass 3M which is placed on a…

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Q: A force of 3 N is applied to a spring. The spring is not stretched beyond the limit of…

A: Given Force F = 3 N Increase in length x = 15 cm =0.15 m

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.95 x 102 N/m that lies…

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Q: A block with mass e.50 kg is forced against a horizontal spring of negligible mass, compressing the…

A: Given: Compression of the spring  = x = 0.24 m Mass of the block = m = 0.5 kg Distance block covers…

Q: box is pressed against a horizontal spring, compressing the spring from its relaxed length. The box…

A: Solution: as given K = spring constant of spring X = distance the spring is compressed M = mass box…

Q: The spring return constant of a spring is 2000 N/m.  How much will it crash in metres if a 100 kg…

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Q: A block of mass of 1.0 kg is moving across a frictionless floor and comes in contact with an ideal…

A: Given data :                Mass of the block , m = 1 kg                Velocity of the block,  v =…

Q: a) Find the the work required to stretch the spring.   (b) Find the speed the block has as it…

A: Given, Mass of the block= 2 kg Force constant of the spring k=4.70×102 N/m The initial position of…

Q: A bullet with mass 4.74 g is fired horizontally into a 2.131 kg block attached to a horizontal…

A:

Q: A 2.50-kg block on a horizontal floor is attached to a horizontal spring that is initially…

A: Using work-energy theorem Kf+Uf-Wnc=Ki+Ui0+0+μkmgd=0+12kx2d=kx22μkmg

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 5.30 x 102 N/m that lies…

A: a)Work done to stretch the spring = (1/2)(K)(displacement)2  = (1/2)(530)(0.048)2 W =0.61 Joules

Q: A 46 g ice cube can slide up and down a frictionless 38° slope. At the bottom, a spring with spring…

A: Given m = 46g =0.046kg Δx = 6cm = 0.06m K = 24N/m

Q: A box of mass m = 10 kg moves with a speed Vo-4.5 ms on a frietionless horizoutal floor as shown in…

A: Given: The mass of the box is m=10 kg. The velocity is V0=4.5 m/s. The spring constant is k=5 kN/m.…

Q: A bullet with mass 5.00 g is fired horizontally into a 2.000-kg block attached to a horizontal…

A: Given:- A bullet with mass m1 = 5.00 g = 5 x 10-3 kg  A block mass of m2 = 2.0 kg  The spring has a…

Q: A box is pressed against a horizontal spring, compressing the spring from its relaxed length. The…

A: Solution: (1)  Maximum height attained by the box is only depends on angle of projection and initial…

Q: A ball of mass m is launched straight upward from a spring of constant k compressed by a distance x.…

A: Given Data : The mass of the ball is given as m The spring constant of the spring is given as k The…

Q: A block of mass m = 0.6 kg slides on a horizontal rough surface head on into a spring of spring…

A: Given:  Block's mass, m=0.6 kg Block distance from spring, x=1.1 m Block velocity, v=3.82 m/s Spring…

Q: The cable of the 1600 kg elevator cab in the figure snaps when the cab is at rest at the first…

A: Given: The mass of the elevator is 1600 kg. The distance from the bottom is 3.1 m. The spring…

Q: A block of mass m = in front of a relaxed horizontal spring of spring constant k = 200 N/m fixed at…

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Q: A 4.00 kg block is attached to a spring of force constant 500 N/m. The block is pulled 10.0 cm to…

A: Given Mass of block m= 4kg Spring constant K=500N/m x=0.1 m Coefficient of friction μ=0.25

Q: A box of mass 10 kg slides along a frictionless surface with a velocity of v = 8.0 m/s and hits a…

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Q: what is the velocity of the block vf in m/s?

A: Friction will perform negative work and decrease total mechanical energy of spring block system .…

Q: A student pushes the 1.00 kg block in the figure below against a horizontal spring, compressing it…

A: Given Data : The spring is compressed by the student by a distance given as xc = 0.180 m.  The mass…

Q: A 500-g block is released from rest and slides down a frictionless track that begins 1.00 m above…

A: Mass of the block is m = 500 g Height of the block is h = 1 m Spring constant is k = 35 N/m

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.