A 12-g bullet is fired into a 3.0 kg ballistic pendulum initially at rest and becomes embedded in it. The pendulum subsequently rises a vertical distance of 12 cm. What was the initial speed of the bullet (in m/s)? Option 1 Option 2 Option 3 Option 4 Option 5 24 446 512 640 385
Q: 30. As shown in Figure P9.30, a bullet of mass m and speed v passes completely through a pendulum…
A: Given that the mass of the bullet is m, its speed before collision is v, the mass of the bob is M,…
Q: Two balls moving in opposite directions have velocities v1i,x = 12_m/s and v2i,x = -6.4_m/s. If…
A:
Q: A 2.0-g particle moving at 5.8 m/s makes a perfectly elastic head-on collision with a resting 1.0-g…
A: Given, Masses, Initial velocities,
Q: A body of 2.0 kg moving to 3.0 m/s hits an object of 1.0 kg initially at rest. Immediately after the…
A: Figure representing the resolution of velocity vector of mass 2 Kg after the collision
Q: A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface.…
A: Whenever there is collision between two bodies, the energy and momentum of the system remains…
Q: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and…
A: Given:- mass is m = 0.0065 kg block is M = 0.92 kg system swings and reaches a maximum height of h…
Q: A 2.0 g particle moving at 7.8 m/s makes a perfectly elastic head-on collision with a resting 1.0 g…
A:
Q: A 10 g bullet is fired into a 2 kg ballistic pendulum as shown in the figure. The bullet remains in…
A:
Q: 3.8.15. [Level 2] Two particles A and B strike each other as shown. ma = 2 kg and mg = 1.2 kg. Just…
A: Given data: The mass of particle A is mA=2 kg. The mass of particle B is mA=1.2 kg. The velocity of…
Q: 1. A force of 5250 N is applied to a 300 kg box for 3.5 s. The box is initially at rest on a…
A: a) Impulse =Change in momentum =Force×Duration of the force =5250×3.5 N.s=18375 N.s≈1.8×104 N.s
Q: Byoink! A pendulum of mass M₁ = 3.50 [kg] is released from rest at a height of 0.500 [m] from the…
A: Apply the energy conservation equation between the height and the ground for mass M1.
Q: A 2.0-g particle moving at 5.4 m/s makes a perfectly elastic head-on collision with a resting 1.0-g…
A: Given a 2.0-g particle moving at 5.4 m/s makes a perfectly elastic head-on collision with a resting…
Q: student fires a 0.07 kg arrow at an object with mass m that is initially at rest on a frictionless…
A: Given:mass of arrow, m1=0.07 kgmass , m2=6.1 kginitial velocity of mass 1, u1=90 m/sinitial velocity…
Q: A 2.0-g particle moving at 8.2 m/s makes a perfectly elastic head-on collision with a resting 1.0-g…
A: The condition for the velocity of the incident particle after the collision,…
Q: A bullet of mass 20 g, traveling at 350 m/s , strikes a steel plate at an angle of 30° with the…
A: calculate the impulse along the parallel to the plane of plate Iparallel= m(Vfcosθ – Vicosθ) =…
Q: A 10.0 kg shell is traveling in the positive x-direction at 25.0 m.s-1 relative to the ground when…
A: Given M is 10 Kg m1 is 3Kg m2 is 7Kg V = 25 m/s V1 is in positive x direction Concept is…
Q: A ball of mass 0.165 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to…
A:
Q: A ballistic pendulum system fires a bullet into a pendulum bob suspended by a rod of negligible…
A:
Q: Table 3:Total Momentum TOTAL INITIAL MOMENTUM (kg.m/s) COLLISION TOTAL FINAL PERCENTAGE DIFFERENCE…
A: Table 3: Total momentum Elastic collision: The percentage difference, %…
Q: A 2.0-g particle moving at 8.2 m/s makes a perfectly elastic head-on collision with a resting 1.0-g…
A:
Q: A 2.7 kg block of wood sits on a frictionless table. A 3.0 g bullet, fired horizontally at a speed…
A: It is given that,
Q: Particle A has a mass of 5.00 g and particle B has a mass of 1.40 g. Particle A is located at the…
A:
Q: A 0.0200-kg bullet is shot horizontally and collides with a 3.65-kg block of wood. The bullet embeds…
A: We can solve the above question using conservation of momentum and work-energy theorem. Note:- as…
Q: mass 6500 kg and traveling at 95 km/h, collide head-on and come to rest. The mechanical energy lost…
A: Impulse = change in momentum Impulse = 6500×(0-95×5÷18) Impulse= 171527.77kgm/s
Q: bullet (mass of 210 grams) is shot horizontally with a velocity of 120 m/s to strike a ballistic…
A:
Q: 10 cm A bullet of mass m = 10.0 g strikes a stationary vertical ballistic pendulum (B) of mass M =…
A: Given, mass of bullet, m = 10 g = 0.010 kg mass of ballistic pendulum, M = 2.75 kg maximum…
Q: Q12: In a collinear collision, a particle with an initial speed V,strikes a stationary particle of…
A:
Q: A ballistic pendulum system fires a bullet into a pendulum bob suspended by a rod of negligible…
A: (A) For Bullet, Mass m1 = 0.025 Kg Initial speed of bullet v1i = 1.20 m/s Initial momentum of…
Q: A 3.00-g bullet is fired horizontally into a 10.0-kg block of wood suspended by a rope from the…
A: Given that:Mass of bullet, m=3.00 gMass of block, M=10.0 kg=10000 gHeight of the system after…
Q: In a ballistic pendulum experiment, a small marble is fired into a cup attached to the end of a…
A:
Q: A 2.4 kg ball falling vertically hits the floor with a speed of 2.5 m/s and rebounds with a speed of…
A: Impulse is equal to chnage in momentum of the ball.
Q: A 5.0 g bullet traveling horizontally with a velocity of magnitude 400 m/s is fired into a wooden…
A: The linear momentum of a system remains constant (in magnitude and direction) if the external forces…
Q: A 3.0-kg object moving in the positive x direction has a one-dimensional elastic collision with a…
A: Given. m1=3kg m2=5kg u2=0 V2=6m/s =speed of 5kg block after collision Let u1=speed of 3kg block…
Q: A 2.0-g particle moving at 6.0 m/s makes a perfectly elastic head-on collision with a resting 1.0-g…
A: Collision is the phenomenon where two bodies interact with each other, thus leading to the change in…
Q: A bullet, m = 2.00 kg, traveling with a velocity of 60.0 m/s strikes and embeds itself in the bob of…
A: m = 2 kg v = 60 m/sM = 8 kg using conservation of momentum 2*60 = (2+8)V V = 120/10V = 12 m/s
Q: A 10 g bullet is fired into a 2 kg ballistic pendulum as shown in the figure. The bullet remains in…
A: For an object of mass m and speed v kept at a height h above the reference level, The momentum p of…
Q: 13. A rifle bullet with mass 8.00 g strikes and embeds itself in a block with a mass of 0.992 kg…
A: Given,
Q: A 2.8 kg block of wood sits on a frictionless table. A 3.0 g bullet, fired horizontally at a speed…
A: Given ms of wooden block = 2.8 kg mass of bullet = 3.0 g speed of bullet before collision = 510…
Q: Q12: In a collinear collision, a particle with an initial speed V, strikes a stationary particle of…
A: Let m be the mass of both particles, v1 be the velocity of the first particle after the collision,…
Q: please help me with all the parts, there are 4 total parts attached as 2 screenshots
A:
Q: A 2.0-g particle moving at 7.6 m/s makes a perfectly elastic head-on collision with a resting 1.0-g…
A:
Q: A 4.00 kg object is moving at 5.00 m/s SOUTH. It strikes a 3.00 kg object that is moving WEST at…
A:
Q: A bullet of mass m = 7.50 g is fired horizontally with a speed v = 549 m/s into a bob of a ballistic…
A:
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
- A .150kg baseball is thrown directly upwards with a velocity of 20.0m/s. 1.00 second later an 8.00g bullet is fired upwards at the baseball with a velocity of 300m/s. The bullet collides and embeds itself in the ball. Find the maximum height of the bullet/ball pair.A small ball of mass mb = 0.050 kg is projected into a pendulum of mass Mp = 0.200 kg in a ballistic pendulum experiment. How fast does the ball need to go in order to get the pendulum to swing up to a height of h = 0.25 m abov its original position? O 11.1 m/s 0.553 m/s 2.21 m/s 0.111 m/sA 28 g rifle bullet is fired at a 3.1 kg ballistic pendulum hanging on a 2.8 m long string and embeds itself, which makes the pendulum swing upward in an arc. Determine the bullets initial velocity if the pendulum’s maximum y-displacement is 0.2 m. Your answer should have 4 significant figures. The bullets initial velocity is _____ m/s.
- An object of mass 3kg moving with an initial velocity of 51 m/s., collides with and sticks to an object of mass 2kg with an initial velocity of -3j m/s. Find the final velocity of the composite object (in m/s)? Option 1 Option 2 Option 3 Option 4 Option 5 5j (3i-1.2) (2.1-3) (3î+4) 4.2îA radioactive nucleus at rest decays into a second nucleus, an electron, and a neutrino. The electron and neutrino are emitted at right angles and have momenta of Pe=9.67x10-23 kg. m/s and p = 5.99×10-23 kg. m/s. respectively. (Figure 1) Figure Pnuc nuc +y 0 Onuc Py Pe 1 of 1 +X Part A Determine the magnitude of the momentum of the second (recoiling) nucleus. Express your answer to three significant figures and include the appropriate units. Pnuc= Submit Part B Onuc = Submit μA 4 Provide Feedback Value Request Answer Determine the angle between the momentum of the electron and the momentum of the second (rec Express your answer using three significant figures. [VE| ΑΣΦ 1 → C Request Answer Units 1 ? ?I got this question wrong, I got 0.161 meaters as my final answer can someone please give me detailed steps on my process? An 26 g rifle bullet traveling at 370 m/s buries itself in a 4.8 kg pendulum hanging on a 2.2 m long string, which makes the pendulum swing upward in an arc. Determine the maximum vertical displacement of the pendulum (height).(g = 9.8 m/s2)
- 2 m length 0.01 kg ED 1.5 kg plz help using g = 9.8 0.40 m A bullet of mass 0.010 kg moving horizontally strikes a block of wood of mass 1.50 kg which is suspended as a pendulum. The bullet lodges in the wood, and together they swing upward a maximum distance of 0.400 m. What was the speed of the bullet just before it struck the wooden block? Express your answer in m/s.Two masses are held against springs, each are compressed by 25.0 cm. Both are released from rest, travel across the frictionless ground, and stick together when they collide. Find the velocity (magnitude and direction) of both masses right after the collision. m2 = 350 g ki = 42.5 N/m k2 = 30.0 N/m m, = 200 g 25.0 cm 25.0 cm 9.A 0.02-kg bullet collides with a 5.75-kg pendulum. After the collision, the bullet remains embedded onto the pendulum and the pair swings up to a maximum height of 0.386m. What is the initial speed of the bullet?
- 4. A 2.0 kg block hangs from the end of a 1.5 kg, 1.0-m long rod, together forming a pendulum that swings from a frictionless pivot at the top end of the rod. A 10 g bullet is fired horizontally into the block where it sticks, causing the pendulum to swing out to a 30° angle. What was the speed of the bullet? (5 marks) m,-0.010 kg d=1.0 m m=1.5 kg mg2.0 kg Ves=0 m/s4. [-14 Points] DETAILS HRW10 9.XP.018. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A 2.00 kg "particle" traveling with velocity V, = (3.7 m/s) i collides with a 3.40 kg "particle" traveling with velocity v, = (2.0 m/s)j. The collision connects the two particles. (a) What then is their velocity in unit-vector notation? m/s ) i + ( m/s ) i (b) Express this velocity in magnitude-angle notation. magnitude m/s direction (counterclockwise from the positive x axis) Additional Materials eBook Submit Assignment Save Assighment Progress Home My Assignments +Request Extension 10:15 PM O Type here to search N O 16. 3/21/2021 hp insert prt sc delete fg f5 fe 144 esc % ho %24 4 %23 backspace 00 5A 31.6-g rifle bullet traveling 221. m/s buries itself in a 2.11-kg pendulum hanging on a 2.45-m-long string, which makes the pendulum swing upward in an arc. Determine how high (in m) the pendulum swings above its original position.