A block of mass M rests over the gap between two tables, as in the figure. A wad of sticky clay with mass m is shot up between the tables so that it sticks to the block and lifts the block-clay conglomerate to a maximum height h off the table. Calculate the clay's kinetic energy just before its collision with the block if M = 2.5 kg, m = 6.6 g, and h = 3.4 mm. (Hints: Be careful with units. The correct final expression is not K₁ = (M+ m) gh. Kinetic energy is lost during the collision!) K₁ = M J
A block of mass M rests over the gap between two tables, as in the figure. A wad of sticky clay with mass m is shot up between the tables so that it sticks to the block and lifts the block-clay conglomerate to a maximum height h off the table. Calculate the clay's kinetic energy just before its collision with the block if M = 2.5 kg, m = 6.6 g, and h = 3.4 mm. (Hints: Be careful with units. The correct final expression is not K₁ = (M+ m) gh. Kinetic energy is lost during the collision!) K₁ = M J
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i got this answer wrong. it comes out to 31.7199
Transcribed Image Text:Computation
A block of mass M rests over the gap between two tables, as in the
figure. A wad of sticky clay with mass m is shot up between the tables
so that it sticks to the block and lifts the block-clay conglomerate to a
maximum height h off the table. Calculate the clay's kinetic energy
just before its collision with the block if M = 2.5 kg, m = 6.6 g, and
h = 3.4 mm.
(Hints: Be careful with units. The correct final expression is not
K₁ = (M + m) gh. Kinetic energy is lost during the collision!)
K₁ =
M
m
J
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