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A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 63 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 128 kWh. At a = 0.05, can your support the claim? Complete parts (a) through (e). (a) Identify Ho and H. Choose the correct answer below. Ο A. Ho: us 900 Ha:μ>900 (claim) OC. Ho: H=860 (claim) H₂: H860 OE. Ho: >860 (claim) H₂: H≤860 OB. Ho: S860 Ha: >860 (claim) O D. Ho: >900 (claim) H₂: μs 900 OF. Ho: H=900 Ha: μ#900 (claim)

A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 63 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 128 kWh. At a = 0.05, can your support the claim? Complete parts (a) through (e). (a) Identify Ho and H. Choose the correct answer below. Ο A. Ho: us 900 Ha:μ>900 (claim) OC. Ho: H=860 (claim) H₂: H860 OE. Ho: >860 (claim) H₂: H≤860 OB. Ho: S860 Ha: >860 (claim) O D. Ho: >900 (claim) H₂: μs 900 OF. Ho: H=900 Ha: μ#900 (claim)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 63 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 128 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. O A. Ho: ≤900 Ha: μ>900 (claim) OC. Ho: μ-860 (claim) H₂: H860 CD O E. Ho: >860 (claim) H₂: H≤860 OB. Ho: S860 OD. Ho: >900 (claim) Η:με 900 OF. Ho: 900 Ha: >860 (claim) OB. The critical values are + t Identify the rejection region(s). Select the correct choice below. OA. The rejection region is z <1.64. OB. The rejection regions are z< -1.64 and z> 1.64. OC. The rejection region is z> 1.64. (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) OA. The critical value is (c) Find the standardized test statistic. Use technology. The standardized test statistic is z =. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Ha: μ#900 (claim) (e) Interpret the decision in the context of the original claim. At the 5% significance level, there enough evidence to electricity consumption in a certain region O A. Fail to reject Ho because the standardized test statistic is not in the rejection region. OB. Reject Ho because the standardized test statistic is in the rejection region. OC. Fail to reject Ho because the standardized test statistic is in the rejection region. OD. Reject Ho because the standardized test statistic is not in the rejection region. kWh. the claim that the mean monthly residential
Transcribed Image Text:A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 63 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 128 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. O A. Ho: ≤900 Ha: μ>900 (claim) OC. Ho: μ-860 (claim) H₂: H860 CD O E. Ho: >860 (claim) H₂: H≤860 OB. Ho: S860 OD. Ho: >900 (claim) Η:με 900 OF. Ho: 900 Ha: >860 (claim) OB. The critical values are + t Identify the rejection region(s). Select the correct choice below. OA. The rejection region is z <1.64. OB. The rejection regions are z< -1.64 and z> 1.64. OC. The rejection region is z> 1.64. (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) OA. The critical value is (c) Find the standardized test statistic. Use technology. The standardized test statistic is z =. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Ha: μ#900 (claim) (e) Interpret the decision in the context of the original claim. At the 5% significance level, there enough evidence to electricity consumption in a certain region O A. Fail to reject Ho because the standardized test statistic is not in the rejection region. OB. Reject Ho because the standardized test statistic is in the rejection region. OC. Fail to reject Ho because the standardized test statistic is in the rejection region. OD. Reject Ho because the standardized test statistic is not in the rejection region. kWh. the claim that the mean monthly residential
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