A gas mixture contains 14.4 mol of NO and 6.25 mol of Br2.(a) Compute the mole fraction of NO in the mixture. (b) The mixture is then allowed to stand, and the NO starts to react with the Br2 to give NOBr: 2NO(g) + Br2(g) ----> 2NOBr(g) At a certain point in the reaction, 2.50 mol of NOBr is present. Determine the mole fraction of NO in the new mixture.

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Chapter6: Thermochemisty
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A gas mixture contains 14.4 mol of NO and 6.25 mol of Br2.

(a) Compute the mole fraction of NO in the mixture.

(b) The mixture is then allowed to stand, and the NO starts to react with the Br2 to give NOBr:

2NO(g) + Br2(g) ----> 2NOBr(g)


At a certain point in the reaction, 2.50 mol of NOBr is present. Determine the mole fraction of NO in the new mixture.

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