A manufacturer of automobiles finds that 15% of the cars are unfit for delivery when they come off the assembly line. A worker proposes a new assembly technique which he claims will reduce the percentage of unfit cars. His technique is tried on 80 randomly chosen cars. It turns out that 3 are defective. Test at α = 0.05. Show all seven steps to receive full cred
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A manufacturer of automobiles finds that 15% of the cars are unfit for delivery when they come off the
assembly line. A worker proposes a new assembly technique which he claims will reduce the percentage of
unfit cars. His technique is tried on 80 randomly chosen cars. It turns out that 3 are defective.
Test at α = 0.05. Show all seven steps to receive full credit.
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- A manufacturer wants to increase the shelf life of a line of cake mixes. Past records indicate that the average shelf life of the mix is 231 days. After a revised mix has been developed, a sample of nine boxes of cake mix gave these shelf lives (in days): 230,233, 235, 236, 233, 240, 240, 241, and 237. Using α = 0.025, has the shelf life of the cake mix increased? Multiple Choice Yes, because computed t is greater than the critical value. Yes, because computed t is less than the critical value. No, because computed t lies in the region of acceptance. No, because 236.11 is quite close to 231.A car manufacturer aims to improve the quality of the products by reducing the defects and also increase the customer satisfaction. Therefore, he monitors the efficiency of two assembly lines in the shop floor. In line A there are 18 defects reported out of 200 samples. While the line B shows 25 defects out of 600 cars. At α 5%, is the differences between two assembly procedures are significant?A sample of 800 truck drivers from Minnesota were interviewed randomly and 316 answered they like tunnels. Determine if the sample evidence shows that less than half of the truck drivers like tunnels. Use α=0.05.
- In North America, between 100 million and 1 billion birds die each year by crashing into windows on buildings, more than any other human-related cause. This figure represents up to 5% of all birds in the area. One possible solution is to construct windows angled downward slightly so that they reflect the ground rather than an image of the sky to a flying bird. An experiment by Klem et al. (2004) compared the number of birds that died as a result of vertical windows, windows angled 20 degrees off vertical, and windows angled 40 degrees off vertical. The angles were randomly assigned with equal probability to six windows and changed daily; assume for this exercise that windows and window locations were identical in every respect except angle. Over the course of the experiment, 30 birds were killed by windows in the vertical orientation, 15 were killed by windows set at 20 degrees off vertical, and 8 were killed by windows set at 40 degrees off vertical. a. Clearly state an appropriate…Use the figure to the right, which shows the percentages of adults from several countries who favor building new nuclear power plants in their country. The survey included random samples of 1115adults from Country A, 1021 adults from Country B,1038 adults from Country C, and 1067 adults from Country D. At α=0.04, can you reject the claim that the proportion of adults in Country C who favor building new nuclear power plants in their country is greater than the proportion of adults from Country D who favor building new nuclear power plants in their country? Assume the random samples are independent. Country A: 54%. Country B: 51%. Country C: 48%. Country D:37%. Part A: Choose the correct answer. A. H0:p1>p2 Ha:p1≤p2 B. H0:p1≤p2 Ha:p1>p2 C. H0:p1<p2 Ha:p1≥p2 D. H0:p1=p2 Ha:p1≠p2 E. H0:p1≠p2 Ha:p1=p2 F. H0:p1≥p2 Ha:p1<p2 Find the standardized test statistic. Use technology to calculate the P-value. Decide whether to reject or fail to reject the…To test the effectiveness of a new drug designed to relieve flu symptoms, 200 patients were randomly selected and divided into two equal groups. One group of 100 patients was given a pill containing the drug while the other group of 100 was given a placebo. What can we conclude about the effectiveness of the drug if 62 of those actually taking the drug felt a beneficial effect while 41 of the patients taking the placebo felt a beneficial effect? Use α = 0.05.
- A manufacturer claims that it has increased the shelf life of a line of cake mixes. Past records indicate that the average shelf life of the mix is 216 days. After a revised mix has been developed, a sample of six boxes of cake mix gave these shelf lives (in days): 215, 217, 218, 219, 216, and 217.Using α = 0.05, test the manufacturer claim that the shelf life of the cake mix is more than 216 days. a- Standard Deviation b- Testing a mean, Calculated c- Critical mean, Table d- p-value e-What do we conclude?A manufacturer wants to increase the shelf life of a line of cake mixes. Past records indicate that the average shelf life of the mix is 234 days. After a revised mix has been developed, a sample of nine boxes of cake mix gave these shelf lives (in days): 232,238, 238, 239, 236, 243, 243, 244, and 240. At a = 0.05, the manufacturer wants to test if the shelf life of the cake mix increased. What critical value must be used for this test?A manufacturer of carpet wanted to reduce the number of flaws per square yard of carpet. Data gathered from quality control measures indicated that Brand A typically had 2.5 flaws per square yard. A mechanical engineer for the company developed a modification of the current process that she thought might reduce the number of flaws. To determine if this was true, one of the machines in the plant was modified according to her specifications. A sample of 30 square yards of carpet was analyzed for flaws. The sample yielded a mean of 2.2 flaws per square yard. Assume the standard deviation of the measurements is 0.66. Find the p-value of the test. A) 0.62 B) 0.0124 C)0.9938 D) 0.0062
- In North America, between 100 million and 1 billion birds die each year by crashing into windows on buildings, more than any other human-related cause. This figure represents up to 5% of all birds in the area. One possible solution is to construct windows angled downward slightly, so that they reflect the ground rather than an image of the sky to a flying bird. An experiment by Klem et al. (2004) compared the number of birds that died as a result of vertical windows, windows angled 20 degrees off vertical, and windows angled 40 degrees off vertical. The angles were randomly assigned with equal probability to six windows and changed daily; assume for this exercise that windows and window locations were identical in every respect except angle. Over the course of the experiment, 30 birds were killed by windows in the vertical orientation, 15 were killed by windows set at 20 degrees off vertical, and 8 were killed by windows set at 40 degrees off vertical. . Clearly state an appropriate…The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured automobile drivers were intoxicated. A random sample of 27 records of automobile driver fatalities in Kit Carson County, Colorado, showed that 15 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 77% in Kit Carson County? Use α = 0.01. Solve the problem using both the traditional method and the P-value method. Since the sampling distribution of p̂ is the normal distribution, you can use critical values from the standard normal distribution as shown in the table of critical values of the z distribution. (Round the test statistic and the critical value to two decimal places. Round the P-value to four decimal places.) test statistic = critical value = P-value = State your conclusion in the context of the application. There is sufficient evidence at the 0.01…A manufacturer of carpet wanted to reduce the number of flaws per square yard of carpet. Data gathered from quality control measures indicated that Brand A typically had 2.5 flaws per square yard. A mechanical engineer for the company developed a modification of the current process that she thought might reduce the number of flaws. To determine if this was true, one of the machines in the plant was modified according to her specifications. A sample of 30 square yards of carpet was analyzed for flaws. The sample yielded a mean of 2.2 flaws per square yard. Assume the standard deviation of the measurements is 0.66. A. Not statistically significant at the 0.05 level B. Not practically significant at the 0.05 level C. statistically significant at the 0.05 level D.Practically significant at the 0.05 level
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