A manufacturer of metal plates makes two claims concerning the thickness of the plates they produce. The manufacturer claims that Statement a: The mean is 200mm Statement b : The variance is 1.5mm squared To investigate the second claim the thickness of a second sample of metal sheets was measured. The values found are listed in Part b with mm as unit. Set up the framework of an appropriate statistical test on Statement B Explain how knowing the sample variance before carrying out the test would influence the structure of the test.

A manufacturer of metal plates makes two claims concerning the thickness of the plates they produce. The manufacturer claims that Statement a: The mean is 200mm Statement b : The variance is 1.5mm squared To investigate the second claim the thickness of a second sample of metal sheets was measured. The values found are listed in Part b with mm as unit. Set up the framework of an appropriate statistical test on Statement B Explain how knowing the sample variance before carrying out the test would influence the structure of the test.

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter8: Sequences, Series, And Probability

Section8.CR: Chapter Review

Problem 37E: Find the positive geometric mean between 4 and 64.

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Find the positive geometric mean between 4 and 64.
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Sub. Grp Reading-1 53.59 Reading-2 Reading-3 50.74 Reading-4 Reading-5 48.61 50 39 46.84 50.74 51.10 48.97 51.45 46.84 3. 51.81 49.32 50.03 49.32 47.90 4 53.23 47.90 51.10 50.39 50.74 50.03 50.03 46.84 47.19 51.10 6. 52.52 46.48 48.26 47.90 47.90 53.23 46.84 48.97 5145 50.03 8. 51.45 52.16 50.03 47.90 51.81 55.01 47.90 47.19 47.90 48. 26 10 51.10 47.90 48.61 49.68 49.32 11 51.10 49.32 50.03 50.03 50.39 12 52.16 48 26 51.10 51.81 49.32 51.10 46.48 50.03 50.39 13 S145 51.81 48.61 49.32 14 53.23 50.39 54.30 48.97 49.68 49.68 48.26 15 For the above given schedule. X-chart value of: UCL CL= LCL= R-chart value of: UCL = CL - LCL = Given that: D5 = 2.115 and A5 - 0.577 Approximate answers to TWO Decimal places.
62.3 65.9 73 79.9 82 89.1 92.8 97.6|78.8 || 82.4 95|70.2|79.4 82.7 91.8 72.7 78.6 94 70.6 75.6 82.9 73.5 78.6 78.2 79.8 76.3 71.4 77.8 87 77.8 85.9 8185.1 81 83.5 68.887.683.5| 94 85.7 86.2 79.6 80.6 86.7 72.4 88.6 66 81.6 76 |72.4 || 80.8 || 74.1 || 66.8 | 81.2|| 73 || 90.3| 79 83.7 82 84.2 81 67.6 82.9 71 98.6 86.5 88.3 82.7 86.7 81.4 What is the range of this data set? range = 36.3 Report the standard deviation using the rounding rules suggested in class (two more decimal places than the data reports). standard deviation =