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- Write a racket code to fill where it is shown bellow #lang racket(require rackunit) ;.......................................... (define total-error(lambda (list-of-pairs)'YOUR-CODE-HERE )) (check-equal? (total-error '((2 -7) (-4 -20) (7 8) (-13 2)))Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)The below code is written in C++, can you please write it in Scheme language with comments or explination? thank you!! void antiSymmetric(int b[], int sizeOfB) { bool hold = true; // set hold to true for(int i = 0; i < sizeOfB;) // for each pair (e,f) in b { if(hold == false) { cout << "AntiSymmetric - No" << endl; break; //Did not find (e,e) in b } for(int j = 0; j < sizeOfB;) { if(b[i] == b[j+1] && b[i+1] == b[j]) //If true, then pair(f,e) exists { if(b[i+1] != b[i]) //If true, relation is antisymmetric { hold = true; break; } else { hold = false; j = j + 2; } } else { hold = false; j = j + 2; } } i = i + 2;
- In C++, write a program that outputs the nodes of a graph in a breadth first traversal. Data File: Please use this data file. Text to copy: 100 1 3 -9991 4 -9992 5 -9993 2 -9994 -9995 7 8 -9996 4 7 -9997 -9998 -9999 7 8 -999 Diagram: Also, please take a look at the attached figure on and calculate the weights for the following edges: 0 -> 1 -> 4 0 -> 3 -> 2 -> 5 -> 7 0 -> 3 -> 2 -> 5 -> 8 6 -> 4 6 -> 7 9 -> 7 9 -> 8 To calculates these weights, please assume the following data: 0 -> 1 = 1 0 -> 3 = 2 1 -> 4 = 3 3 -> 2 = 4 2 -> 5 = 5 5 -> 7 = 6 5 -> 8 = 7 6 -> 4 = 8 6 -> 7 = 9 9 -> 7 = 10 9 -> 8 = 11In C++, write a program that outputs the nodes of a graph in a breadth first traversal. Data File: Please use this data file. Text to copy: 100 1 3 -9991 4 -9992 5 -9993 2 -9994 -9995 7 8 -9996 4 7 -9997 -9998 -9999 7 8 -999 Diagram: Also, please take a look at figure 20-6 on page 1414 and calculate the weights for the following edges: 0 -> 1 -> 4 0 -> 3 -> 2 -> 5 -> 7 0 -> 3 -> 2 -> 5 -> 8 6 -> 4 6 -> 7 9 -> 7 9 -> 8 To calculates these weights, please assume the following data: 0 -> 1 = 1 0 -> 3 = 2 1 -> 4 = 3 3 -> 2 = 4 2 -> 5 = 5 5 -> 7 = 6 5 -> 8 = 7 6 -> 4 = 8 6 -> 7 = 9 9 -> 7 = 10 9 -> 8 = 11solve in C please. Implement the following two functions that get a string, and compute an array of non-emptytokens of the string containing only lower-case letters. For example:● For a string "abc EFaG hi", the list of tokens with only lower-case letters is ["abc", "hi"].● For a string "ab 12 ef hi ", the list of such tokens is ["ab","ef","hi"].● For a string "abc 12EFG hi ", the list of such tokens is ["abc","hi"].● For a string " abc ", the list of such tokens is ["abc"].● For a string "+*abc!! B" the list of such tokens is empty.That is, we break the string using the spaces as delimiters (ascii value 32), and look only at thetokens with lower-case letters only .1. The function count_tokens gets a string str, and returns the number ofsuch tokens.int count_tokens(const char* str);For example● count_tokens("abc EFaG hi") needs to return 2.● count_tokens("ab 12 ef hi") needs to return 3.● count_tokens("ab12ef+") needs to return 0.2. The function get_tokens gets a string str, and…
- Let float javaSqrt(int x) be a Java implementation of this square root function (assume it throws an exception if x is negative). Discuss the differ ences between sqrt and javaSqrt when considered as mathematical functions between sets.The aim of this question is to ensure that you are able to write C language codethat carries out recursive computations by using loops. Before attempting to solvethis problem, please study the loop programming exercises on this link:https://codeforwin.org/c-programming/for-do-while-loop-programming-exercises. Write C program that will prompt the user for an integer n. If the user hasentered a non-integer, the user must be prompted again until he or she enters aninteger. If he enters non-integer numbers five times, the program must inform theuser the following message‘You have entered non-integers on five occasions, now the program is exiting”before coming to an end.On the other hand, if the user enters an integer n, the program must compute thesum of three consecutive factorials S=n!+(n+1)!+(n+2)! . Your program mustprint the resulting sum on the display.We have the following rectangle records in a list of dictionaries. Test Cases: rectangle_records = [{"ID": "Rect1", "Length": 40, "Breadth": 25, "Color": "red"}, {"ID": "Rect2", "Length": 30, "Breadth": 20, "Color": "blue"}, {"ID": "Rect3", "Length": 70, "Breadth": 45, "Color": "green"}, {"ID": "Rect4", "Length": 20, "Breadth": 10, "Color": "purple"}] Using Insertion Sort, Write a python function sort_rectangles that takes rectangle_records and record_title as a parameter and sort the rectangle_records in ascending order by record_title. You need to return the updated rectangle_records list. NOTE: The type of record_title input can be ID, Length, Breadth, or Color. >>> sort_rectangles(rectangle_records, "ID") [{"ID": "Rect1", "Length": 40, "Breadth": 25, "Color": "red"}, {"ID": "Rect2", "Length": 30, "Breadth": 20, "Color": "blue"}, {"ID": "Rect3", "Length": 70, "Breadth": 45, "Color": "green"}, {"ID": "Rect4", "Length": 20, "Breadth": 10, "Color": "purple"}] >>>…
- Implement an postfix-to-infix translator using stacks. The applicationshould repeatedly read a postfix expression and print the equivalentinfix expression until the user quits. Throw an exception if the postfixexpression entered is invalid.Please do this in JAVA PROGRAMMING. Given: List L of pairs of charactersString SOutput: TRUE if S is a valid string, FALSE otherwise. A string is considered valid if each character in the string can be paired with another character in the string, where the pair belongs to the input list L. Furthermore, two pairs cannot cross each other. In other words, a pair most completely enclose another, or be completely separate. Design and implement an efficient dynamic programming solution to this problem. Examples: Input L: (a b) (b c) (c d) (a a) Input S: aaba Output: True (pairs shown color-coded: aaba, "aa" fully encloses "ab") Input L: (a b) (b c) (c d) (a a) Input S: abcaad Output: True (pairs shown color-coded: abcaad, "ab" is separate from the other pairs) Input L: (a b) (b c) (c d) (a a) Input S: acbd Output: False (acbd is not valid because the pairs cross each other.) Input L: (a b) (b c) (c d) (a a) Input S: aaac Output: FalsePlease help. How to solve this on Java language by using only Dynamic Programming? Thank you. We are given a set A of integers. Check whether we can partition A into three subsets with equal sums. It is important to note that all elements should be included in the equally divided subsets; no element should be left out, and none of the elements should be repeated in the subsets.For example: A={4,7,6,2,10,7,10,2} has such a partition: {4,2,10}, {7,7,2},{6,10}Input: A set, A, of integersOutput: if we can partition A into three subsets with equal sums, print subsets otherwise present a suitable message.