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A parent of mass m₂ = 60 kg sits on a uniform beam seesaw of mass M = 40 kg, at a distance r₁ = 1.0 m to the right of the pivot P (as pictured below). Each end of the beam is equidistant from P. a) What distance r, to the left should a child of mass m, = 30 kg sit in order to balance the seesaw (hint: the center of mass of the beam is right at its center, since it is taken to be uniform)? Show any equations you use, or justify your intuition. m₂ = 30 kg m, = 60 kg M = 40 kg P √₂ = ? r₁=1.0 m b) What is the torque exerted by the weight of the parent, the torque from the child's weight, and the torque from the seesaw weight (magnitude and direction for each case, with direction indicated as into or out of the paper, and state the proper units)?

A parent of mass m₂ = 60 kg sits on a uniform beam seesaw of mass M = 40 kg, at a distance r₁ = 1.0 m to the right of the pivot P (as pictured below). Each end of the beam is equidistant from P. a) What distance r, to the left should a child of mass m, = 30 kg sit in order to balance the seesaw (hint: the center of mass of the beam is right at its center, since it is taken to be uniform)? Show any equations you use, or justify your intuition. m₂ = 30 kg m, = 60 kg M = 40 kg P √₂ = ? r₁=1.0 m b) What is the torque exerted by the weight of the parent, the torque from the child's weight, and the torque from the seesaw weight (magnitude and direction for each case, with direction indicated as into or out of the paper, and state the proper units)?

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
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Problem 5OQ: Assume a single 300-N force is exerted on a bicycle frame as shown in Figure OQ10.5. Consider the...
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A parent of mass m₂ = 60 kg sits on a uniform beam seesaw of mass M = 40 kg, at a distance r = 1.0 m to the right of the pivot P (as pictured below). Each end of the beam is equidistant from P. a) What distance r, to the left should a child of mass m₂ = 30 kg sit in order to balance the seesaw (hint: the center of mass of the beam is right at its center, since it is taken to be uniform)? Show any equations you use, or justify your intuition. m₂ = 30 kg m₁ = 60 kg M = 40 kg P r₂ = ? r₁=1.0 m b) What is the torque exerted by the weight of the parent, the torque from the child's weight, and the torque from the seesaw weight (magnitude and direction for each case, with direction indicated as into or out of the paper, and state the proper units)?
Transcribed Image Text:A parent of mass m₂ = 60 kg sits on a uniform beam seesaw of mass M = 40 kg, at a distance r = 1.0 m to the right of the pivot P (as pictured below). Each end of the beam is equidistant from P. a) What distance r, to the left should a child of mass m₂ = 30 kg sit in order to balance the seesaw (hint: the center of mass of the beam is right at its center, since it is taken to be uniform)? Show any equations you use, or justify your intuition. m₂ = 30 kg m₁ = 60 kg M = 40 kg P r₂ = ? r₁=1.0 m b) What is the torque exerted by the weight of the parent, the torque from the child's weight, and the torque from the seesaw weight (magnitude and direction for each case, with direction indicated as into or out of the paper, and state the proper units)?
Consider the same seesaw (M = 40 kg and length L = 5.0 m), but now the pivot P is at the far end with a child of m₂ = 30 kg sitting a distance r, = 4.0 m to the left of the pivot. To balance the net torque on the beam, a perpendicular rope that can exert a torque via upwards tension force is attached to the beam at a distance r = 1.0 m from the pivot. Calculate the upward force F (tension in the rope) in terms of M, m₂, r₂, r, L, and g, and then plug in the values above to find the force F that is needed for equilibrium. m₂ M L 2 -I F P
Transcribed Image Text:Consider the same seesaw (M = 40 kg and length L = 5.0 m), but now the pivot P is at the far end with a child of m₂ = 30 kg sitting a distance r, = 4.0 m to the left of the pivot. To balance the net torque on the beam, a perpendicular rope that can exert a torque via upwards tension force is attached to the beam at a distance r = 1.0 m from the pivot. Calculate the upward force F (tension in the rope) in terms of M, m₂, r₂, r, L, and g, and then plug in the values above to find the force F that is needed for equilibrium. m₂ M L 2 -I F P
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