A plywood disk of radius 20.0 cm and mass 2.20 kg has a small hole drilled through it, 2.00 cm from its edge. The disk is hung from the wall by means of a metal pin through the hole and is used as a pendulum. What is the period of the pendulum for small oscillations? The moment of inertia for a disk about the center of mass is Icm = 1½- MR². 2 1.08 s Pin 2.00 cm R = 20.0 cm M = 2.20 kg
A plywood disk of radius 20.0 cm and mass 2.20 kg has a small hole drilled through it, 2.00 cm from its edge. The disk is hung from the wall by means of a metal pin through the hole and is used as a pendulum. What is the period of the pendulum for small oscillations? The moment of inertia for a disk about the center of mass is Icm = 1½- MR². 2 1.08 s Pin 2.00 cm R = 20.0 cm M = 2.20 kg
Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter3: Oscillations
Section: Chapter Questions
Problem 3.45P: A grandfather clock has a pendulum length of 0.7 m and mass bob of 0.4 kg. A mass of 2 kg falls 0.8...
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![A plywood disk of radius 20.0 cm and mass 2.20 kg has a small hole drilled through it, 2.00 cm from
its edge. The disk is hung from the wall by means of a metal pin through the hole and is used as a
pendulum. What is the period of the pendulum for small oscillations? The moment of inertia for a disk
about the center of mass is Icm = 1½- MR².
2
1.08 s
Pin
2.00 cm
R = 20.0 cm
M = 2.20 kg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe582bbe8-a980-40be-b244-7538bf9c76fe%2Fff667ff4-7c56-4ce0-bf8d-945d31b31913%2F8rhxyu_processed.png&w=3840&q=75)
Transcribed Image Text:A plywood disk of radius 20.0 cm and mass 2.20 kg has a small hole drilled through it, 2.00 cm from
its edge. The disk is hung from the wall by means of a metal pin through the hole and is used as a
pendulum. What is the period of the pendulum for small oscillations? The moment of inertia for a disk
about the center of mass is Icm = 1½- MR².
2
1.08 s
Pin
2.00 cm
R = 20.0 cm
M = 2.20 kg
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