A positive charge (q= +6.0 µC) starts from point A in a constant electric field and accelerates to point B. The work done by the electric force is WAB = +1.7 x 103 J. Determine the potential difference VB-VA between the two points. Be sure to include the proper algebraic sign.

A positive charge (q= +6.0 µC) starts from point A in a constant electric field and accelerates to point B. The work done by the electric force is WAB = +1.7 x 103 J. Determine the potential difference VB-VA between the two points. Be sure to include the proper algebraic sign.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Electric Potential

Section: Chapter Questions

Problem 25.12OQ: A particle with charge -40.0 nC is on the x axis at the point with coordinate x = 0. A second...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A positive charge (q= +6.0 µC) starts from point A in a constant electric field and accelerates to point B. The work done by the electric
force is WAB = +1.7 x 103 J. Determine the potential difference VB - VA between the two points. Be sure to include the proper algebraic
sign.
VB-VA= Number i
Units
A
E
E

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