A solution of phenol (HC6H50) is prepared by dissolving 0.385 g of phenol in 2.00 L of H2O. The solution has a pH = 6.29. Determine the value of Ka for phenol. ( PREV 1 2 Based on your ICE table and definition of Ka, set up the expression for Ka and then evaluate it. Do not combine or simplify terms. Ka 5 RESET [0] [0.385] [6.29] [4.09 x 10] [2.05 x 10] [5.1 x 10-7] [0.799] 1.3 x 10-10 7.8 x 10° 4.0 x 103 2.5 x 10-4
A solution of phenol (HC6H50) is prepared by dissolving 0.385 g of phenol in 2.00 L of H2O. The solution has a pH = 6.29. Determine the value of Ka for phenol. ( PREV 1 2 Based on your ICE table and definition of Ka, set up the expression for Ka and then evaluate it. Do not combine or simplify terms. Ka 5 RESET [0] [0.385] [6.29] [4.09 x 10] [2.05 x 10] [5.1 x 10-7] [0.799] 1.3 x 10-10 7.8 x 10° 4.0 x 103 2.5 x 10-4
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter14: Acids And Bases
Section: Chapter Questions
Problem 30QRT
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![A solution of phenol (HC,H;0) is prepared by dissolving 0.385 g of phenol
in 2.00 L of H20. The solution has a pH = 6.29. Determine the value of Ka
for phenol.
( PREV
1
2
Based on your ICE table and definition of Ka, set up the expression for Ka and then
evaluate it. Do not combine or simplify terms.
Ka =
%3D
5 RESET
[0]
[0.385]
[6.29]
[4.09 x 10-]
[2.05 x 10]
[5.1 x 10-7]
[0.799]
1.3 x 10-10
7.8 x 10°
4.0 x 103
2.5 x 10-4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb67f5b4f-9f96-4f2f-93ec-c2762b2db8a1%2F0f97ac9e-2e3f-4a5b-9d5d-581a30e43895%2Fhbzyggrj_processed.png&w=3840&q=75)
Transcribed Image Text:A solution of phenol (HC,H;0) is prepared by dissolving 0.385 g of phenol
in 2.00 L of H20. The solution has a pH = 6.29. Determine the value of Ka
for phenol.
( PREV
1
2
Based on your ICE table and definition of Ka, set up the expression for Ka and then
evaluate it. Do not combine or simplify terms.
Ka =
%3D
5 RESET
[0]
[0.385]
[6.29]
[4.09 x 10-]
[2.05 x 10]
[5.1 x 10-7]
[0.799]
1.3 x 10-10
7.8 x 10°
4.0 x 103
2.5 x 10-4
![A solution of phenol (HC6H;O) is prepared by dissolving 0.385 g of phenol
in 2.00 L of H20. The solution has a pH = 6.29. Determine the value of Ka
for phenol.
1
2
NEXT >
Based on the given values, fill in the ICE table to determine concentrations of all
reactants and products.
HC6H;0(aq) +
H2O(1)
H3O*(aq)
C6H5O¯(aq)
+
Initial (M)
Change (M)
Equilibrium
(M)
5 RESET
0.385
6.29
-6.29
4.09 x 103
-4.09 x 10-3
2.05 x 10-3
-2.05 x 103
5.1 x 10-7
-5.1 x 10-7
0.799
-0.799](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb67f5b4f-9f96-4f2f-93ec-c2762b2db8a1%2F0f97ac9e-2e3f-4a5b-9d5d-581a30e43895%2F64xiz4l_processed.png&w=3840&q=75)
Transcribed Image Text:A solution of phenol (HC6H;O) is prepared by dissolving 0.385 g of phenol
in 2.00 L of H20. The solution has a pH = 6.29. Determine the value of Ka
for phenol.
1
2
NEXT >
Based on the given values, fill in the ICE table to determine concentrations of all
reactants and products.
HC6H;0(aq) +
H2O(1)
H3O*(aq)
C6H5O¯(aq)
+
Initial (M)
Change (M)
Equilibrium
(M)
5 RESET
0.385
6.29
-6.29
4.09 x 103
-4.09 x 10-3
2.05 x 10-3
-2.05 x 103
5.1 x 10-7
-5.1 x 10-7
0.799
-0.799
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