A stone, projected vertically upward with initial velocity 112 ft/sec, moves according to s = 112t - 16t², s is the distance from the ground. What is the maximum height reached by the stone?
A stone, projected vertically upward with initial velocity 112 ft/sec, moves according to s = 112t - 16t², s is the distance from the ground. What is the maximum height reached by the stone?
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
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Transcribed Image Text:A stone, projected vertically upward with initial velocity 112ft/sec, moves according to s = 112t — 16t²,
s is the distance from the ground. What the maximum height reached by the stone?
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