a system that supports 8 MB of physical memory and has 4096 entries in its inverted page table, the page size is type your answer. KB.
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- Following is a mapping of Logical Memory to Physical Memory using a Page Table. You are required to fill the Page Table: Physical Memory 1 Page 5 Logical Memory Page 0 2 Page 2 Page 1 3 Page 4 Page 2 4 Page 3 5 Page 0 Page 4 6 7 Page 1 8 Page 3 Page 5 Page Table 1 3.The memory location at address 00002001 contains the memory variable in binary form. What is the data memory variable in hexadecimal form? MEMORY 1110 1011 00002001 1110 1010 00002000 1110 1001 00001999 1110 1000 00001998 1110 0111 00001997 1110 0110 00001996 DATA ADDRESS The data memory variable in hexadecimal form is E7. a. b. The data memory variable in hexadecimal form is EA. The data memory variable in hexadecimal form is EB. C. The data memory variable in hexadecimal form is E9. Od.Given the following: Logical Memory size of 1000 Physical Memory size of 2000 Page (and frame) size of 100 Block A contains data for a program Select Block A’s size and its starting point in both memories. Then write the page table for Block A based on your selections. See below for the layout of both memories and an example of Block A of size 200. Logical Memory Physical Memory location/ page location/frame 0 to 99/ 0 0 to 99/ 0 100 to 199 /1 Block A 100 to 199/ 1 200 to 299/ 2 Block A 200 to 299/ 2 300 to 399/ 3 300 to 399/ 3 400 to 499/ 4 400 to 499/ 4 500 to 599/ 5 500 to 599/ 5 600 to 699/ 6 600 to 699/ 6 700 to 799/ 7 700 to 799/ 7 800 to 899/ 8 800 to 899/ 8 900 to 999/ 9 900 to 999/ 9 1000 to 1099/ 10 1100 to 1199/ 11 1200 to 1299/ 12 1300 to 1399/ 13 Block A 1400 to 1499/ 14 Block…
- Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Page Table Physical Memory Physical Address (starting) Oxppppdddd Page Frame Frame Size (hex) Size (dec) Ox10000 Ox10000 2 Охс000 65536 PPpp: page number dddd: page offset 1 1 Оxd000 65536 3 2 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x00011119 What is the physical address for 0x00000001 What is the logical address for Oxd0000001 ? What is the logical address for Oxc0000002 ?Computer Science This question is about paging-based virtual memory A computer has a virtual-momory space of 250MB (megabytes) The computer has 325) of primary memory. The pige som s-4000 by the address is 1011 0001 0101 1110 0010 1010 0010 a. How many frames can it have? b. Which of the bits in the virtual address correspond to the Page number? c. Which of the bits correspond to the page offset?Assignment LRU paging A program has the following page reference string 0123342453346256 If we allocate 3 page frames to the program, 1. How many page faults will be generated?
- pard / My coOurses / EECP1290 / SECTIONS ASSESSMENTS/Section 5 Oui-2 Movina 10 חכ y=2 while y<=99: print (y) i+=7 et red ed out of g question is the increment value. vious page - Section-5 Quiz-1 Jump to...the oneratinn 3) Suppose an application program requires 2500H bytes of memory for its code, 2FOH bytes of memory for its data, and 2A0H bytes of memory for its stack. Shows how this application is positioned in a memory with a 20-bit address bus if locations 00000OH to 0A000H is reserved for the operating system (OS) softtware.How does multithreading improve the performance of a program? Give specific scenarios where multithreading is beneficial.
- In MPLAB PIC16F84A Design an algorithm that compares two 3-byte numbers. •Each number is large enough to require 24 bits of 3 bytes of space. (You need 3 addresses for each of them) •There are three possible outcomes (Greater, equal, and lesser). Each outcome leads to a separate subroutine. •Subroutines are not important they can be empty. •Greater Subroutine sets RB0 •Equal Subroutine sets RB1 •Lesser Subroutine sets RB2 Thank you.With virtual memory, when a program requests memory,the memory management system does which of the following? Select one: A. It grants the request as long as there is enough physical memory to accommodate B. It looks up the address in the page table. If the address is in memory, then it grants the request. C. It looks up the address in the page table. If the address is in memory, it grants the request. If the address is stored to disk, it writes a section of memory to disk and then transfers the requested virtual memory address from disk to main memory. D. It causes a deadlock to occur.Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Physical Memory Physical Address (starting) Page Table Охрppdddd Page | Frame Frame Size (hex) Size (dec) 2 Охс000 Ox10000 65536 pppp: page number dddd: page offset 1 1 Оxd000 Ox10000 65536 3 2 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x0002ffff What is the physical address for Ox0000abcd ? What is the logical address for Oxf000000f ? What is the logical address for Oxc000bbcc ?