A theoretical heat engine is illustrated in the diagram below. This engine uses 1.0 kg of nitrogen gas (RN2 = 0.2968 m³.kPa/kg∙K) as the working fluid inside the piston-cylinder devise. Calculate the integral below for this cycle. What does the value of the integral tell you about the cycle? T₁ = 600 K Energy source P₁ = 2 MPa at TH T₁ = 300 K 4 P4 = 184.4 kPa V4 = 0.4829 m³/kg Insulation TH=const. Он (a) Process 1-2 TH FE Energy sink at TL Q₁ (d) Process 4-1 T= const. SQ = : ? T Insulation TH TL (b) Process 2-3 T₂ = 600 K P2 = 1.5 MPa V2 0.1187 m³/kg = EE (c) Process 3-4 T3 = 300 K P3 = 138.4 kPa V3 = 0.6434 m³/kg
A theoretical heat engine is illustrated in the diagram below. This engine uses 1.0 kg of nitrogen gas (RN2 = 0.2968 m³.kPa/kg∙K) as the working fluid inside the piston-cylinder devise. Calculate the integral below for this cycle. What does the value of the integral tell you about the cycle? T₁ = 600 K Energy source P₁ = 2 MPa at TH T₁ = 300 K 4 P4 = 184.4 kPa V4 = 0.4829 m³/kg Insulation TH=const. Он (a) Process 1-2 TH FE Energy sink at TL Q₁ (d) Process 4-1 T= const. SQ = : ? T Insulation TH TL (b) Process 2-3 T₂ = 600 K P2 = 1.5 MPa V2 0.1187 m³/kg = EE (c) Process 3-4 T3 = 300 K P3 = 138.4 kPa V3 = 0.6434 m³/kg
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:A theoretical heat engine is illustrated in the diagram below. This engine uses 1.0 kg of nitrogen gas
(RN2 = 0.2968 m³.kPa/kg∙K) as the working fluid inside the piston-cylinder devise. Calculate the
integral below for this cycle. What does the value of the integral tell you about the cycle?
T₁ = 600 K
Energy
source
P₁ = 2 MPa
at TH
T₁ = 300 K
4
P4 = 184.4 kPa
V4 = 0.4829 m³/kg
Insulation
TH=const.
Он
(a) Process 1-2
TH
FE
Energy
sink
at TL
Q₁
(d) Process 4-1
T= const.
SQ
= : ?
T
Insulation
TH
TL
(b) Process 2-3
T₂ = 600 K
P2 = 1.5 MPa
V2 0.1187 m³/kg
=
EE
(c) Process 3-4
T3
= 300 K
P3 = 138.4 kPa
V3 = 0.6434 m³/kg
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