A/if y=sin(x), z=cos(x), v=y+x, where (-100 ≤x≤100) could you plot y, z, v as shown below: 05 50 D
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Control structures
Control structures are block of statements that analyze the value of variables and determine the flow of execution based on those values. When a program is running, the CPU executes the code line by line. After sometime, the program reaches the point where it has to make a decision on whether it has to go to another part of the code or repeat execution of certain part of the code. These results affect the flow of the program's code and these are called control structures.
Switch Statement
The switch statement is a key feature that is used by the programmers a lot in the world of programming and coding, as well as in information technology in general. The switch statement is a selection control mechanism that allows the variable value to change the order of the individual statements in the software execution via search.
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- A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum ofits digits at even places is either 0 or divisible by 11.For example, for 2547039:(Sum of digits at odd places) - (Sum of digits at even places) = (9 + 0 + 4 + 2) - (3 + 7 + 5) = 0So 2547039 is divisible by 11.But for 13165648:(Sum of digits at odd places) - (Sum of digits at even places) = (8 + 6 + 6 + 3) - (4 + 5 + 1 + 1) = 1212 is not divisible by 11 so 13165648 is also not divisible by 11.A number is divisible by 11 if the difference of the sum of its digits at odd places and the sum ofits digits at even places is either 0 or divisible by 11.For example, for 2547039:(Sum of digits at odd places) - (Sum of digits at even places) = (9 + 0 + 4 + 2) - (3 + 7 + 5) = 0So 2547039 is divisible by 11.But for 13165648:(Sum of digits at odd places) - (Sum of digits at even places) = (8 + 6 + 6 + 3) - (4 + 5 + 1 + 1) = 1212 is not divisible by 11 so 13165648 is also not divisible by 11.Sample run:Give your number: 13165648Total is: 1213165648 is not divisible by 11.Write a program that calculate the values of (X + Y) x (X – Y) where X, Y = 0, 1, 2, …, 9and prints the following table:X|Y 0 1 2 3 4 5 6 7 8 90| 0 -1 -4 -9 -16 -25 -36 -49 -64 -811| 1 0 -3 -8 -15 -24 -35 -48 -63 -802| 4 3 0 -5 -12 -21 -32 -45 -60 -773| 9 8 5 0 -7 -16 -27 -40 -55 -724| 16 15 12 7 0 -9 -20 -33 -48 -655| 25 24 21 16 9 0 -11 -24 -39 -566| 36 35 32 27 20 11 0 -13 -28 -457| 49 48 45 40 33 24 13 0 -15 -328| 64 63 60 55 48 39 28 15 0 -179| 81 80 77 72 65 56 45 32 17 0
- ISBN-13 is a new standard for identifying books. It uses13 digits d1d2d3d4d5d6d7d8d9d10d11d12d13. The last digit d13 is a checksum, which iscalculated from the other digits using the following formula: 10 - (d1 + 3d2 + d3 + 3d4 + d5 + 3d6 + d7 + 3d8 + d9 + 3d10 + d11 + 3d12)%10If the checksum is 10, replace it with 0. Your program should read the input as astring. Here are sample runs: Enter the first 12 digits of an ISBN-13 as a string: 978013213080 ↵EnterThe ISBN-13 number is 9780132130806evaluate and interpret the condition numbre por f(x)=sin(x)/(1+cos(x)) for x0=1.0001*piISBN-13 is a new standard for identifying books. It uses 13 digits d1d2d3d4d5d6d7d8d9d10d11d12d13. The last digit d13 is a checksum, which is calculated from the other digits using the following formula: 10 - (d1 + 3d2 + d3 + 3d4 + d5 + 3d6 + d7 + 3d8 + d9 + 3d10 + d11 + 3d12)%10 If the checksum is 10, replace it with 0. Your program should read the input as a string.
- HALP m + n = 2k + 2k = 4k therefore adding even numbers always gives an even number. The above is wrong because.... it doesn't consider the case when adding to odd numbers m and n are different so you cannot use 2k for both it doesn't consider what m and n are for particular values in the integers it doesn't consider the case when m is even and n is oddA B C D X1 a1 b1 c3 L X2 a2 b1 c1 L X3 a2 b2 c1 H X4 a2 b2 c2 H X5 a2 b1 c1 L X6 a2 b2 c1 H X7 a2 b1 c2 H X8 a1 b2 c2 L Using the table above, calculate the following, there measures (1) Cosine. a) A1 ==> L b) A2, B2 ==> H c) A2, C2 ==> HGiven two numbers, return true if the sum of both numbers is less than 100. Otherwise return false. Examples lessThan100 (22, 15) → true // 22 + 15 = 37 less Than100 (83, 34) // 83 + 34 = 117 - false less Than100 (3, 77) → true
- Rahul is a maths genius so he came up with a game and as raj is Rahul's best friend so Rahul decided to play the game with raj. Rahul gives raj two numbers LL and RR and asks raj to find the count of numbers in the range from LL to RR (LL and RR inclusive) which are a digit palindromic. A number is a digit palindromic if its first digit is the same as its last digit. As raj is not very good at maths so your task is to help Raj find out how many numbers are a digit palindromic in the range LL to RR. For example if LL = 88 and RR = 2525 .The following numbers are a digit palindromic in the range of LL to RR: 8, 9, 11, and 22. If LL = 12511251 and RR = 12661266. The digit palindromic numbers are 1251 and 1261. Input format The first line contains an integer denoting the number of test cases. Each test case is described by a single line that contains two integers LL and RR. Output format For each test case output, an integer denoting how many a digit palindromic numbers are there in the…Given the following NDFSM M, the correct statements are: q0 8 b a q1 94 a b a a q2 q5 a 93 L(M) = {w € {a, b}*: w contains aaa or bab or w| is even). OL(M) = {w € {a, b}*: w contains aaa or bab or w| is odd}. L(M) = {w € {a,b}*: The 2nd to the last character of w is a or|w| is even}. L(M) = {w = {a, b}*: The 2nd to the last character of w is a or |w| is odd}.I am what you call a perfectionist. I always strive for perfection, and I appreciate everyone and everything that is perfect. That is why I have recently acquired an appreciation for perfect numbers! I absolutely need to know which numbers from 1 to 1000 are considered perfect. From what I recall, a perfect number is a positive integer that is equal to the sum of all its divisors other than itself. Example: 6 is a perfect number because the divisors of 6 other than itself are 1, 2, and 3, and 1 + 2 + 3 = 6. c++ code