An object is travelling in 1-dimension (i.e. along the x- axis) with a velocity described by the equation: v(t)=v0+1/6st^3 , where s and v0 are constants. The object’s position, and acceleration at time t = 0 are given by d0, and a0 respectively. In terms of the variables given, what is the average acceleration of the object over the interval from 0 to 2 seconds.

An object is travelling in 1-dimension (i.e. along the x- axis) with a velocity described by the equation: v(t)=v0+1/6st^3 , where s and v0 are constants. The object’s position, and acceleration at time t = 0 are given by d0, and a0 respectively. In terms of the variables given, what is the average acceleration of the object over the interval from 0 to 2 seconds.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 10P: An object moves along the x axis according to the equation x = 3.00t2 2.00t + 3.00, where x is in...

See similar textbooks

Similar questions

An object moves along the x axis according to the equation x = 3.00t2 2.00t + 3.00, where x is in meters and t is in seconds. Determine (a) the average speed between t = 2.00 s and t = 3.00 s, (b) the instantaneous speed at t = 2.00 s and at t = 3.00 s, (c) the average acceleration between t = 2.00 s and t = 3.00 s, and (d) the instantaneous acceleration at t = 2.00 s and t = 3.00 s. (e) At what time is the object at rest?
A car moves on a straight road such that its position from a reference point is given by the following function:{ x(t) = 3 + 5t + 2t2 + 0.4t3, y(t) = 0, z(t) = 0 }where t is in seconds and x in meters. Find the average velocity, in meters per second, in the x-direction between t1 = 0.25 s and t2 = 1.85 s. Find the average acceleration, in meters per second squared, in the x-direction between t1 = 0.25 s and t2 = 1.85 s.
An unidentified flying object (UFO) is observed to travel a total distance of 49000 m, starting and ending at rest, over a duration of 3.07 s. Assuming the UFO accelerated at a constant rate to the midpoint of its journey and then decelerated at a constant rate the rest of the way, what was the magnitude of its acceleration? Express your answer in g s , where 1 g = 9.81 m/s^2. 20,796 g s 10,398 g s 2,120 g s 1,060 g s
An object's position in the x-direction as a function of time is given by the expression; x(t) = 5t2 + 2t where are quantities have proper SI Units. What is the object's average velocity in the x-direction between the times t = 1.35 s and t = 2.3 s. Just enter the number rounded to 3 significant figures and assume it has proper SI Units.
An unidentified flying object (UFO) is observed to travel a total distance of 19000 m, starting and ending at rest, over a duration of 4.23 s. Assuming the UFO accelerated at a constant rate to the midpoint of its journey and then decelerated at a constant rate the rest of the way, what was the magnitude of its acceleration? Express your answer in g s , where 1 g = 9.81 m/s^2.
An object's position in the x-direction as a function of time is given by the expression; x(t) = 5t2 + 2t where are quantities have proper SI Units. What is the object's average velocity in the x-direction between the times t = 1.3 s and t = 2.28 s.
An object's position as a function of time in one dimension is given by the expression; 3.89t2 + 2.22t + 7.48 where are constants have proper SI Units. What is the object's average velocity between the times t = 3.16 s and t = 8.38 s? with everything in 3 sig figs
A helicopter is ascending vertically with a speed of 5.30 m/s. At a height of 107 m above the Earth, a package is dropped from the helicopter. How much time does it take for the package to reach the ground? [Hint: What is v0 for the package?] Express your answer to three significant figures and include the appropriate units. My Answer is that t= 4.163 but what unit is it? I tried s, m/s, min but none of them were correct. PLEASE HELP CONFIRM MY ANSWER and THE UNIT along with 4.163
In reaching her destination, a backpacker walks with an average velocity of 1.31 m/s, due west. This average velocity results, because she hikes for 6.93 km with an average velocity of 2.06 m/s due west, turns around, and hikes with an average velocity of 0.688 m/s due east. How far east did she walk (in kilometers)?
A student solving a physics problem for the velocity of an object has applied appropriate physics principles and obtained the expression v=d/t−v0, where d=35.0meter, t=9.00second, and v0 =3.00meter/second. What is the velocity v?
A particle is moving horizontally with constant acceleration. The position (x, in meters) as a function of time (t, in seconds) is given by x= 0.798 t^2 + 0.3552 t + 0.0355. Based on this information, the acceleration of the particle is what?
An object's position as a function of time in one dimension is given by the expression; 3.89t2 + 2.22t + 7.48 where are constants have proper SI Units. What is the object's average velocity between the times t = 3.16 s and t = 8.38 s?