Assume a program is made of 120 instructions. How many clock cycles are needed to run the whole program in a 5-stage pipelined architecture? Assume there is no branch and complex instruction in the program.
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![Assume a program is made of 120 instructions. How many clock
cycles are needed to run the whole program in a 5-stage
pipelined architecture?
Assume there is no branch and complex instruction in the
program.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F46e255ad-cb0d-4fca-9f96-981f10a59d4f%2F621b07f0-e7d6-400e-b340-b9e163226e33%2Fm50szdf_processed.jpeg&w=3840&q=75)
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- _____ is a CPU design technique in which instruction execution is divided into multiple stages and different instructions can execute in different stages simultaneously.If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Create a stack-based program which computes: 7 & (9 | 8). Your answer should include an illustration which shows the state of the stack after each instruction and show the workings of all the calculations that are required.
- In this implementation, each instruction is provided with its own data independently of how other instructions acquire theirs. We insert a(n): A Multiple Input/Output B The Case of Many Pieces of Information or Directions C Unique Information Only One D Several Insts From OneImplement the MOV instruction using assembly language code.transfers the source from the second operand to the first operand (destination).The source operand can be a memory address, a general-purpose register, or an instantaneous value.The destination register may be a memory location or a general-purpose register.Each operand, which may be a byte or a word, must be the same size.Write a microprogram for the following user level instruction, suitable to be executed on the given microarchitecture. The user level instruction is: SP = LSHIFT(IR - AC)
- There are two "backup" instructions for each instruction in a computer instruction set design, which is called orthogonality. Tell us whether this statement is correct or incorrect.Implement assembly language code to MOV instruction copies the second operand (source) to the first operand (destination). the source operand can be an immediate value, general-purpose registeror memory location. the destination register can be a general-purpose register, or memorylocation. both operands must be the same size, which can be a byte or a word.For a computer's instruction set to be orthogonal, it must be able to generate a "backup" instruction for each main instruction. Please correct me if I am in error.
- Expanding opcodes make instruction decoding much easier than when it is not used.Trur or False.Suppose that you have a computer with a memory unit of 24 bits per word. In this computer, the assembly program's instruction set consists of 198 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. a. How many bits are needed for the opcode? b. How many bits are left for the address part of the instruction? c. How many additional instructions could be added to this instruction set without exceeding the assigned number of bits? Discuss and show your calculations.A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word ofmemory.a. How many bits are needed for the opcode?b. How many bits are left for the address part of the instruction?c. What is the maximum allowable size for memory?d. What is the largest unsigned binary number that can be accommodated in one word of memory?
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