By the alternating series test, the series First find the partial fraction decomposition of (六)( +10 k 4(−1)²+1 k=1k(k+ 10) 4 k(k+ 10) 4 k(k + 10) Then find the limit of the partial sums. 4(−1)k+1 k(k + 10) k=1 Enter your answer for the sum as a reduced fraction. converges. Find its sum.
By the alternating series test, the series First find the partial fraction decomposition of (六)( +10 k 4(−1)²+1 k=1k(k+ 10) 4 k(k+ 10) 4 k(k + 10) Then find the limit of the partial sums. 4(−1)k+1 k(k + 10) k=1 Enter your answer for the sum as a reduced fraction. converges. Find its sum.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 26RE
Related questions
Question
![By the alternating series test, the series
First find the partial fraction decomposition of
(六)( +10
k
4(−1)²+1
k=1k(k+ 10)
4
k(k+ 10)
4
k(k + 10)
Then find the limit of the partial sums.
4(−1)k+1
k(k + 10)
k=1
Enter your answer for the sum as a reduced fraction.
converges. Find its sum.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8109dbb5-39b2-442d-b17d-793e299fca4a%2F02e05633-af81-4b89-b58f-1d79e52c5e23%2Ff3olzmp_processed.png&w=3840&q=75)
Transcribed Image Text:By the alternating series test, the series
First find the partial fraction decomposition of
(六)( +10
k
4(−1)²+1
k=1k(k+ 10)
4
k(k+ 10)
4
k(k + 10)
Then find the limit of the partial sums.
4(−1)k+1
k(k + 10)
k=1
Enter your answer for the sum as a reduced fraction.
converges. Find its sum.
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