C++ Given an integer num, repeatedly add all its digits until the result has only one digit, and return it. Example 1: Input: num = 38 Output: 2 Explanation: The process is 38 --> 3 + 8 --> 11 11 --> 1 + 1 --> 2 Since 2 has only one digit, return it. Example 2: Input: num = 0 Output: 0 Constraints: 0 <= num <= 231 - 1 Follow up: Could you do it without any loop/recursion in O(1) runtime?
C++ Given an integer num, repeatedly add all its digits until the result has only one digit, and return it. Example 1: Input: num = 38 Output: 2 Explanation: The process is 38 --> 3 + 8 --> 11 11 --> 1 + 1 --> 2 Since 2 has only one digit, return it. Example 2: Input: num = 0 Output: 0 Constraints: 0 <= num <= 231 - 1 Follow up: Could you do it without any loop/recursion in O(1) runtime?
Programming Logic & Design Comprehensive
9th Edition
ISBN:9781337669405
Author:FARRELL
Publisher:FARRELL
Chapter6: Arrays
Section: Chapter Questions
Problem 7RQ
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Question
C++
Given an integer num, repeatedly add all its digits until the result has only one digit, and return it.
Example 1:
Input: num = 38 Output: 2 Explanation: The process is 38 --> 3 + 8 --> 11 11 --> 1 + 1 --> 2 Since 2 has only one digit, return it.
Example 2:
Input: num = 0 Output: 0
Constraints:
- 0 <= num <= 231 - 1
Follow up: Could you do it without any loop/recursion in O(1) runtime?
//code here
class Solution {
public:
int addDigits(int num) {
}
};
//
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