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![c)
Simplify the expression [(a'nb)v (a v b')]v (a'nb ^c) by using the laws of Boolean
algebra.
d)
Let f(x, y,z, w) = (x'ny'n2'aw') v (x'^ y az'aw') v (x^ y'n2'aw)
v (x^ya2'aw)v (x'ny'nzaw) v (x'^y az^w).
Draw a Karnaugh map and hence find a simplified form of f(x, y, z, w) .](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0cdf8efb-f38e-4f5a-b266-f359a6465af1%2Fcb1f6e2f-6eaa-403a-8e36-b9f76103ccd0%2Fofjxpgj_processed.png&w=3840&q=75)
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- Given A={1,2,3,4,56}, B= {2,4,5,6} and C= (1,6,7} 1. B' U C'=(x^2)/2 + (x^3)/3=gx.A[i][j] = 1 where i = j how do I translate this to c++ programing?It is for a two dimentional matrix, trying to print a diagonal with ones and rest zeros. ex. 1 0 0 0 1 0 0 0 1 ************************************* could you show me this as a pointer function?
- Plot the following function f(x,y) = 1/16(x^2-L^2)(y^2-L^2) over x,y in [-L/2, L/2]. It is important that you use python, and numpy with maskingPython broadcasting. Rewrite the following code without for-loops using vectorization and python broadcasting. (a) Given a data matrix X and vector beta compute a vector yhat: n = X. shape [0] yhat = np.zeros(n) for i in range(n): yhat [i] = beta [0]*X[i, 0] + beta[1]*X[i,1] + beta[2]*X[i, 1]*X[i,2] yhat beta[0]*X[: ,0] + beta[1]*X[:,1] + beta[2]*X[:,1]*X[:,2]What does the following lambda expression compute: λ(x)x × x × x
- TM M = (Q, E, I, 6, 90, 9a, qr), where Q = {90, 91, 92, 9a, 9r}, Σ = {0, 1}, r = {0, 1, L}, and 8 is: 8(qo, U) = (qr, U, R) 8(90, 0) = 8(go, 1) (91, 0, R) (qo, 1, R) = 8(g1, L) = (ga, U, R) 8(91,0) = (91, 0, R) 8(91, 1) = (92, 1, R) = (92, U, R) 8(92, U) 8(92, 0) = (90, 0, R) 8(92, 1) = (92, 1, R) i. Prove that M is NOT a decider. ii. Mathematically describe the language A that M recognises. Prove that A ≤ L(M). iii. Prove A = L(M). iv. Is A Turing-decidable? [Give clear reasons for your answer. No need for a formal proof.]The compass gradient operators of size 3x3 are designed to measure gradients of edges oriented in eight directions: E, NE, N, NW, W, SW, S, and SE. i) Give the form of these eight operators using coefficients valued 0, 1 or – 1. ii) Specify the gradient vector direction of each mask, keeping in mind that the gradient direction is orthogonal to the edge direction.Write a code segment to add two matrices A and B, and store the results in matrix C. C = A+B, that is C[i][j] A[i][j] + B[i][j] The dimensions of both A and B are MxN. Both M and N are defined as constant (final) positive integers, and data types of both matrices are double as shown in the following code segment. double [] [] A = double [][] B = new double [M] [N]; new double [M] [N]; V/ code initialize both A and B /* insert your code here (you need to both define C and perform the sum that populates the values of C) */ ...