Carry out the substitution x = sin 0 in the Taylor series 1.3.5..(2n - 1) x2n+1 arcsin x = x + 2 2.4.6..(2n) 2n +1 n=1 valid for |x| < 1 and use the formula • 7/2 2.4. (2n) 2n+ 0 de = ... 3.5.. (2n + 1)'
Carry out the substitution x = sin 0 in the Taylor series 1.3.5..(2n - 1) x2n+1 arcsin x = x + 2 2.4.6..(2n) 2n +1 n=1 valid for |x| < 1 and use the formula • 7/2 2.4. (2n) 2n+ 0 de = ... 3.5.. (2n + 1)'
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 75E
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Question
![Carry out the substitution x = sin 0 in the Taylor series
1.3.5...(2n – 1) x2n+1
arcsin x = x + ).
2.4.6..(2n)
2n + 1
n=1
valid for |x| < 1 and use the formula
7/2
2.4..(2n)
sin?n+!0 de
0/
3.5..(2n + 1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc661339f-0a99-43d4-a9e8-13db88c16513%2F07f61cb4-3f22-46d7-a164-3fbb37588769%2F61q12xt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Carry out the substitution x = sin 0 in the Taylor series
1.3.5...(2n – 1) x2n+1
arcsin x = x + ).
2.4.6..(2n)
2n + 1
n=1
valid for |x| < 1 and use the formula
7/2
2.4..(2n)
sin?n+!0 de
0/
3.5..(2n + 1)
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