Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns as a number the volume of a pyramid with a rectangular base. Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5 2.1 3.0 is: 9.45 Relevant geometry equations: Volume = base area x height x 1/3 Base area = base length x base width Code writing challenge activity demo 461710.3116374.qx3zqy7 1 '''Enter soution here'''| 2 3 4 length float(input()) 5 width= float(input()) 6 height = float(input()) 7 print (f'Volume for {length} {width} {height} is: {calc_pyramid_volume (length, width, height):.2f}'

Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns as a number the volume of a pyramid with a rectangular base. Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5 2.1 3.0 is: 9.45 Relevant geometry equations: Volume = base area x height x 1/3 Base area = base length x base width Code writing challenge activity demo 461710.3116374.qx3zqy7 1 '''Enter soution here'''| 2 3 4 length float(input()) 5 width= float(input()) 6 height = float(input()) 7 print (f'Volume for {length} {width} {height} is: {calc_pyramid_volume (length, width, height):.2f}'

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter6: User-defined Functions

Section: Chapter Questions

Problem 17PE

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Define a function CalcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a double the volume of a pyramid with a rectangular base. Relevant geometry equations:Volume = base area x height x 1/3Base area = base length x base width.(Watch out for integer division). #include <iostream>using namespace std; /* Your solution goes here */ int main() { double userLength; double userWidth; double userHeight; cin >> userLength; cin >> userWidth; cin >> userHeight; cout << "Volume: " << CalcPyramidVolume(userLength, userWidth, userHeight) << endl; return 0;}
Write a program in C Write a function calledsum_average()whichtakesthree input parameters (x,yand z) of type double. This function willreturn the sumof (x,yand z) andthe averageof those threenumbers. You will need to use two output parametersto accomplish this.Write a program that promptsthe user to enter three numbers and then calls the functionsum_average()to display the resulting sum and average of those numbers.
Write a function rps in Python that returns the result of a game of "Rock,Paper, Scissors". The function accepts two arguments, each one of 'R','P','S' , that represents the symbol played by each of the two players. The function returns: -1 if the first player wins0 if a tie1 if the second player winsScissors beats Paper beats Rock beats Scissors Sample usage: >>> rps('R','P') # player 2 wins, return 11
Define a function which takes one parameter N, and use loop(s) to control and output a pyramid pattern as follows: print a total of N rows, the number of asterisks in each row equals the row number (e.g. the 1st row has 1 asteroid, the Nth row has N asteroids). Note the pattern should be center aligned. E.g. when N is 5, you will print the following pattern * * * * * * * * * * * * * * *
Define a function CoordTransform() that transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew. The function returns void. The transformation is new = (old + 1) * 2. Ex: If xVal = 3 and yVal = 4, then xValNew is 8 and yValNew is 10. #include <iostream>using namespace std; /* Your solution goes here */ int main() {int xValNew;int yValNew;int xValUser;int yValUser; cin >> xValUser;cin >> yValUser; CoordTransform(xValUser, yValUser, xValNew, yValNew);cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl; return 0;} Please help me with this problem using c++.
CHALLENGE ACTIVITY 6.1.5: Function definition: Volume of a pyramid. Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns the volume of a pyramid with a rectangular base.Sample output with inputs: 4.5 2.1 3.0 Volume for 4.5, 2.1, 3.0 is: 9.45 Relevant geometry equations:Volume = base area x height x 1/3Base area = base length x base width. Use Python, please.
Write a function print_shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N : Lather and rinse." num_cycles times, where N is the cycle number, followed by "Done.".Sample output with input: 2 1 : Lather and rinse. 2 : Lather and rinse. Done. Hint: Define and use a loop variable. I have to define a "print_shampoo_instruction" function def shampoo_instructions(num_cycles): if num_cycles < 1: print('Too few.') elif num_cycles > 4: print('Too many.') else: i = 0 while i<num_cycles: print(i + 1,": Lather and rinse.") i = i + 1 print('Done.') def print_shampoo_instructions(num_cycles): print(shampoo_instructions(num_cycles)) return num_cycles ## this is my code user_cycles = int(input())#can not be alter in the programprint_shampoo_instructions(user_cycles)#can not be alter in the program
A = 3 B = 6 C = 9 D= 7 mod10(X) is a function that returns the modulus of X after dividing it to 10. abs(X) is a function that returns the absolute value of X. Examples: mod10(6) = 6, mod10(16)=6, mod10(0) = 0, mod10(15)=5, mod10(41)+12 = 13 abs(4-8) = 4, abs(8-4)=4, abs(2-9) = 7, abs(8-1) = 7, abs(4-4)=0, abs(2-9)+8 = 15 Calculate the following: K1 = mod10(A+B) + 1= ……. K2 = abs(C-D) + 3 = ……. K3 = abs(D-2) + 1 = ……. K4 = mod10(A+B+C+D) + 1 = ……. K1 = mod((A+B), 10) + 1; K2 = abs(C-D) + 3; K3 = abs((D-2)) + 1; K4 = mod((A+B+C+D),10)+1;
Write a function using Java Function Name: winInRowParameters: board: 2D integer array, row: integer, piece: integerReturn: booleanAssume board is valid 2D int array, row is valid index in the board, piece is X==1/O==2Look at indicated row at given index in board. If that row has at least 3 consecutive entries withgiven type of piece (X/O) (3 in a row XXX, OOO), then return true, otherwise false.
A java program where the system should use the following methods: .a) Lagrange interpolation for finding missing values of a function .b) A function implementing multiple application of the trapezoidal rule .c) A function implementing the composite Simpson's rule SHOULD ALLOW THE USER TO : Enter the known values of a function to be integrated or load them from a text file Enter a value of the parameter h and n (the number of intervals) .c) Choose a method to be used
Using C++ Language Define a function CoordTransform() that transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew. The function returns void. The transformation is new = (old + 1) * 2. Ex: If xVal = 3 and yVal = 4, then xValNew is 8 and yValNew is 10. Code: #include <stdio.h> /* Your solution goes here */ int main(void) { int xValNew; int yValNew; int xValUser; int yValUser; scanf("%d", &xValUser); scanf("%d", &yValUser); CoordTransform(xValUser, yValUser, &xValNew, &yValNew); printf("(%d, %d) becomes (%d, %d)\n", xValUser, yValUser, xValNew, yValNew); return 0;}
Write a program in C language that implements a simple hand calculator. The followings arithmetic functions are available on the calculator: addition, subtraction, multiplication, division, cosine, sine and tangent. The result of the function must have the same number of digits of precision as the highest precision operand of the function. An example of the program behavior is shown below. > 8.91 + 1 = 9.91 > 9.61*3.11 = 29.8871 > cos(3.14152759) = 0.99849715