Consider the circuit shown. If you were to solve for the unknown currents using Kirchhoff’s rules, what is the least number of junctions that need to be evaluated? Choose the best answer. One Two Four Six Circuit cannot be evaluated using Kirchhoff’s rules

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter43: Nuclear Physics
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Consider the circuit shown. If you were to solve for the unknown currents using Kirchhoff’s rules, what is the least number of junctions that need to be evaluated? Choose the best answer.

One

Two

Four

Six

Circuit cannot be evaluated using Kirchhoff’s rules

R = 20 N
R3 = 8N
a
b
12
1= 0.52
R2 = 6N
E2
= 3.0 V
Ezi= 12 V
13:= 0.5 2
E= 18|v
12 0.25 2E
E 18 V
+1
f Ra 15 2 e
= 0.75 2
Transcribed Image Text:R = 20 N R3 = 8N a b 12 1= 0.52 R2 = 6N E2 = 3.0 V Ezi= 12 V 13:= 0.5 2 E= 18|v 12 0.25 2E E 18 V +1 f Ra 15 2 e = 0.75 2
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