(Please solve by hand) Consider the differential equationry" - y =-14y* = et, y = u(t)e2tMaking the changes of variablein the differential equation (1), we obtainthe differential equation, u depending on t,u" – bu' – bu = 0.The solution of the differential equation (1), depending on the parameter t, with constant c, andC2, is given by:S¤(t)ela)y(t)et (c1 cos(t/15) + c2 sen(tv/15))S2(t)b)et3(t) = e (cieviB .´z(t)c)y(t)etestS¤(t)= etd)y(t)e* (c1 cos(tv/15) + c2 sen(t/15))

Answered: Image /qna-images/answer/09985da2-f39a-4d5f-8244-075d6dbdd50c.jpg

Consider the differential equation zy" – v = (1) Making the changes of variable * = e', y = u(t)e 2* in the differential equation (1), we obtain the differential equation, u depending on t, u" – 6u' – bu = 0. The solution of the differential equation (1), depending on the parameter t, with constant c, and C2, is given by: a) { 2(t) y(t) ´z(t) et et (c1 cos(tv/15) + c2 sen(t/15)) %3D S¤(t) b) et y(t) ´z(t) c) y(t) et e3 d) { 2(t) l y(t) S¤(t) et et (c1 cos(t/15) + c2 sen(t/15)) || ||

Consider the differential equation zy" – v = (1) Making the changes of variable * = e', y = u(t)e 2* in the differential equation (1), we obtain the differential equation, u depending on t, u" – 6u' – bu = 0. The solution of the differential equation (1), depending on the parameter t, with constant c, and C2, is given by: a) { 2(t) y(t) ´z(t) et et (c1 cos(tv/15) + c2 sen(t/15)) %3D S¤(t) b) et y(t) ´z(t) c) y(t) et e3 d) { 2(t) l y(t) S¤(t) et et (c1 cos(t/15) + c2 sen(t/15)) || ||

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter11: Differential Equations

Section11.1: Solutions Of Elementary And Separable Differential Equations

Problem 54E: Plant Growth Researchers have found that the probability P that a plant will grow to radius R can be...

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