Consider the following C codes: if (53-54) s0 - 51+52; else Below are two MIPS translations. Fill in the blanks. Translation 1: se-s1-52; IF: FALSE: TRUE: EXIT: A B Translation 2: IF: TRUE: FALSE: EXIT: sub 5 add $53, $54, TRUE #branch to TRUE when 53-54 $50, $51, S32 50 s1 - 52 Exit skip the TRUE 550, Ss1, 552 = 50 s1 s2 B Ss3, $54, FALSE #branch to FALSE when s3=s4 $50, Ss1, 5s2 add # 50 = s1 s2 j Exit #skip the FALSE # 50 sub $50, s1 s2 $51, $s2 [Choose ] [Choose] bne beq M >
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- In c++ Now write a program for a double floating pointtype.•What are the number of significant bits that the double’s mantissa can hold, excluding the sign bit.•What is the largest number that a double’s mantissa can hold without roundoff error?•Repeat the program shown on the previous page but set to show where the double’s mantissa starts to exhibit roundoff errors.This problem covers floating-point IEEE 754 format. 1)List four floating-point operations that cause NaN to be created? 2) In the 32-bit (single precision) IEEE 754 format, what is the encoding for negative zero? 3) In the 32-bit (single precision) IEEE 754 format, what is the encoding for positive infinity? 4) Assuming 32-bit (single precision) IEEE 754 format, what decimal number is represent by this word: 1 01111101 00100000000000000000000Given the code Consider the following statements: (1) The code C can correct up to 1 bit error. (2) The minimum distance of code C is 3. Which of the following is correct? Group of answer choices Both statements are TRUE. Only statement (1) is TRUE. Both statements are FALSE. Only statement (2) is TRUE.
- Given are the following codewords for an error control coding scheme data 000 011 100 codeword 00011000 00000111 10101000 . a.What is the minimum Hamming distance? b. What is the coding rate for this scheme? c. what raw data rate would be required if we need a throughput of 6 Mpbs? d. in a different situation, the number of data bits to transfer is 5, and the minimum hamming distance is dmin=5. find the maximum coding rate for this situationI want to write C or C++ functions that evaluate to ONE when the given conditions are true, and to ZERO when they are false. The following are the fourt conditions: int a(int x); //Any bit of x equals 0. int b(int x); // Any bit of x equals 1. int c(int x); //Any bit in the LSB of x equals 0. int d(int x); //Any bit in the MSB of x equals 1. The code should follow the bit-level integer coding rules, with the additional restriction that you may not use equality (==) or inequality (!=) tests.this is for MPI communication using c++ I need the code for ring communication using mpi Let us assume that k people sit at a round table, the first people produce a random number and send it to the second person; the second people produce a random number, add it up to the received number and send the result to the third people. The procedure continues till the last people aggregate all random numbers and send them back to the first people. The first people print off the aggregated result.
- Extend Example 7-36 to write (store) the string below of 28 characters into EEPROM locations starting at address 0x003F. Write one character at a time.MSG[ ] = “All the best for your Final Exam!”Write C expressions, in terms of variable x, for the following values. Your codeshould work for any word size w > 8. For reference, we show the result of evaluatingthe expressions for x = 0x196a45c7, with w = 32.A. The least significant byte of x, with all other bits set to 0. [0x000000c7]B. All but the least significant byte of x complemented, with the least significant byteleft unchanged. [0xe695bac7 ].C. The least significant byte set to all ls’, and all other bytes of x left unchanged[0x196a45ff].4, in the fixed-point machine, the following statement is wrong ( ).A. In addition to the complement, the original code and the inverted code cannot indicate that the original code of −1 B. +0 is not equal to −0C. the inverse of +0 is not equal to the negative of −0 D. For the same machine word length, the complement code can represent a negative number more than the original code and the inverted code.
- Answer the given question with a proper explanation and step-by-step solution. Consider a Hamming (7.4) code in which the parity bits are calculated according to the following equations: r0 = a0 + a1 + a2 r1 = a1 + a2 + a3 r2 = a0 + a1 + a3 The following dataword is to be coded with this scheme: format: a3 a2 a1 a0 0010 What is the parity code for the above dataword? Show it in decimal format for (r2,r1,r0); e.g. if the resulting bits are r2=1, r1=0, r0=0 (100), type the decimal equivalent of 100, which is 4.Compute the weakest precondition for each of the following assignmentstatements and postconditions:1. a = 2 * (b - 1) - 1 {a > 0}2. b = (c + 10) / 3 {b > 6}3. a = a + 2 * b - 1 {a > 1}4. x = 2 * y + x - 1 {x > 11}Implementing AES Implement (almost) the first round of AES with a 128-bit key. Given a 128-bit plaintext and a 128-bit key, this involves: Performing a bitwise XOR with the plaintext and the key Applying byte substitution for each byte in the state Applying shift rows on the state table rows Applying mix columns on the state table columns Output the state table at this point. The "almost" above means that you don't have to perform the XOR with the state and the first sub-key. Please name the program AESEncryptRound.java or aesencryptround.py. You may hard code the inputs. Please use the following inputs, which are the same as given in Appendix B of the FIPS197 document: plaintext = 0x3243f6a8885a308d313198a2e0370734 key = 0x2b7e151628aed2a6abf7158809cf4f3c The byte substitution, multiply-by-2, an multiply-by-3 tables are available at AEStables.txt. Each is given as a list where the ith entry is the value of applying the given operation to i. Please print the state table after each…