Consider the following solution for the dinning philosophers: philosopher(int i) { // i goes from 0 to 4 while(TRUE) { II Think wait(count); wait(fork[i]); wait(fork[(i+1) mod 5]); eat(); signal(count); signal(fork[(i+1) mod 5]); signal(fork[1]), }} semaphore fork[5] = (1,1,1,1,1); semaphore count := 2; We are using the counting semaphore count to count the number of philosophers allowed to eat and we limit them to 2. Is this a good solution? Explain.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Consider the following solution for the dinning philosophers:
philosopher(int i) { // i goes from 0 to 4
while(TRUE) {
I/ Think
wait(count);
wait(fork[i]);
wait(fork[(i+1) mod 5]);
eat();
signal(count);
signal(fork[(i+1) mod 5]);
signal(fork[i]);
}}
semaphore fork[5] := (1,1,1,1,1);
semaphore count := 2;
We are using the counting semaphore count to count the number of philosophers allowed to eat and we limit them to 2. Is this a good solution? Explain.
Transcribed Image Text:Consider the following solution for the dinning philosophers: philosopher(int i) { // i goes from 0 to 4 while(TRUE) { I/ Think wait(count); wait(fork[i]); wait(fork[(i+1) mod 5]); eat(); signal(count); signal(fork[(i+1) mod 5]); signal(fork[i]); }} semaphore fork[5] := (1,1,1,1,1); semaphore count := 2; We are using the counting semaphore count to count the number of philosophers allowed to eat and we limit them to 2. Is this a good solution? Explain.
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