Copper(II) sulfate pentahydrate can be decomposed (dehydrated) by strong heating according the following equation: CuSO4•5 H2O(s) → CuSO4(s) + 5 H2O(l) molar masses (g/mol): CuSO4•5 H2O - 249.7 , H2O - 18.02 How many grams of water will be released when 3.28 g of copper(II) sulfate pentahydrate decomposes?
Copper(II) sulfate pentahydrate can be decomposed (dehydrated) by strong heating according the following equation: CuSO4•5 H2O(s) → CuSO4(s) + 5 H2O(l) molar masses (g/mol): CuSO4•5 H2O - 249.7 , H2O - 18.02 How many grams of water will be released when 3.28 g of copper(II) sulfate pentahydrate decomposes?
Chemistry for Engineering Students
4th Edition
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Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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Copper(II) sulfate pentahydrate can be decomposed (dehydrated) by strong heating according the following equation:
CuSO4•5 H2O(s) → CuSO4(s) + 5 H2O(l)
molar masses (g/mol): CuSO4•5 H2O - 249.7 , H2O - 18.02
How many grams of water will be released when 3.28 g of copper(II) sulfate pentahydrate decomposes?
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