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(d) In what ways are the two sampling distributions of parts (b) and (c) similar? In what ways are they different? (Select all that apply.) Their means are equal. One distribution is not symmetrical. They are both symmetrical. Their means are different. They both cover the same range. One distribution covers a larger range.

(d) In what ways are the two sampling distributions of parts (b) and (c) similar? In what ways are they different? (Select all that apply.) Their means are equal. One distribution is not symmetrical. They are both symmetrical. Their means are different. They both cover the same range. One distribution covers a larger range.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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Just answer the last part (D) Please answer correctly and I'll leave a like 

(b) Use the sample means to construct the sampling distribution of x. Display the sampling distribution as a density histogram. Density 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 6.5 0.0 6 7 6.5 7.5 Sample Mean 8 7 7.5 Sample Mean 8 8.5 8.5 9 9.5 Density DO 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 6.5 0.0 7 6 6.5 7.5 Sample Mean 8 8.5 7 7.5 8 8.5 9 Sample Mean 9.5 Density (c) Suppose that a random sample of size 2 is to be selected, but this time sampling will be done with replacement. Using a method similar to that of part (a), construct the sampling distribution of X. (Hint: There are 16 different possible samples in this case.) 0.8 0.8 0.8 0.8 o 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 0.0 6.5 7 (d) In what ways are the two sampling distributions of parts (b) and (c) similar? In what ways are they different? (Select all that apply.) Their means are equal. One distribution is not symmetrical. They are both symmetrical. Their means are different. They both cover the same range. One distribution covers a larger range. 6 7.5 Sample Mean 6.5 8 8.5 7 7.5 8 8.5 9 Sample Mean 9.5 Density DO 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 6.5 0.0 6 7 6.5 7.5 8 Sample Mean 8.5 7 7.5 8 8.5 9 Sample Mean 9.5 Ⓡ
Transcribed Image Text:(b) Use the sample means to construct the sampling distribution of x. Display the sampling distribution as a density histogram. Density 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 6.5 0.0 6 7 6.5 7.5 Sample Mean 8 7 7.5 Sample Mean 8 8.5 8.5 9 9.5 Density DO 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 6.5 0.0 7 6 6.5 7.5 Sample Mean 8 8.5 7 7.5 8 8.5 9 Sample Mean 9.5 Density (c) Suppose that a random sample of size 2 is to be selected, but this time sampling will be done with replacement. Using a method similar to that of part (a), construct the sampling distribution of X. (Hint: There are 16 different possible samples in this case.) 0.8 0.8 0.8 0.8 o 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 0.0 6.5 7 (d) In what ways are the two sampling distributions of parts (b) and (c) similar? In what ways are they different? (Select all that apply.) Their means are equal. One distribution is not symmetrical. They are both symmetrical. Their means are different. They both cover the same range. One distribution covers a larger range. 6 7.5 Sample Mean 6.5 8 8.5 7 7.5 8 8.5 9 Sample Mean 9.5 Density DO 0.8 Density 0.6 0.4 0.2 0.0 0.6 0.4 0.2 6.5 0.0 6 7 6.5 7.5 8 Sample Mean 8.5 7 7.5 8 8.5 9 Sample Mean 9.5 Ⓡ
Consider the following population: {6, 7, 8, 9). For this population the mean is 6 + 7 + 8 + 9 4 μ = Suppose that a random sample of size 2 is to be selected without replacement from this population. There are 12 possible samples (provided that the order in which observations are selected is taken into account). 8,6 6,7 6,7 6,8 (a) Calculate the sample mean for each of the 12 possible samples. Sample Sample Mean 6,9 7,6 7,8 7,9 8,6 8,7 8,9 = 7.5 9,6 9,7 6,8 6,9 7,6 9,8 7,8 7,9 8,7 8,9 9,6 9,7 9,8
Transcribed Image Text:Consider the following population: {6, 7, 8, 9). For this population the mean is 6 + 7 + 8 + 9 4 μ = Suppose that a random sample of size 2 is to be selected without replacement from this population. There are 12 possible samples (provided that the order in which observations are selected is taken into account). 8,6 6,7 6,7 6,8 (a) Calculate the sample mean for each of the 12 possible samples. Sample Sample Mean 6,9 7,6 7,8 7,9 8,6 8,7 8,9 = 7.5 9,6 9,7 6,8 6,9 7,6 9,8 7,8 7,9 8,7 8,9 9,6 9,7 9,8
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