Determine the moment of inertia of the shaded area about the x-axis. y 13" 2" 11" Parabolic Answer: Ix = i in 4
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- y y 785 mm -19.7 mm --- X 33.5 mm- 384 mm- Built-up Section Typical Section Ix = 4200 x 106 mm* %3D ly = 315 x 106 mm4 Area, A = 40100 mm2 --- I .. Calculate the moment of inertia about the centroidal x-axisDetermine the moment of inertia of the shaded area about the x-axis. OK ←6" 16" Answer: Ix = i in.4Question 2 Determine the moment of inertia of the shaded area with respect ot the x-axis. Where b=17inch and h=16inch h
- The shaded area has the following properties: Ix = 1.26 x106 mm4; Iy = 6.55 x105 mm4; and Pxy = −1.02 105 mm4Determine the moments of inertia of the area about thex’ and v’ axes if θ=30o.Compute the moment of inertia, Ix of the cross-sectional area about the neutral axis. 6 in. 0.8 in. 0.8 in.→ E 8 in. A) 78.49 inn4 B) 49.87 inA4 c) 47.94 in^4 D 17.88 in^4 E) 94.78 inA4 F) 87.49 in^4 G) 2.914 in^4 (H) 5.866 inA48. Determine the horizontal distance by using stadia marks indicated on the metric rod sighting shown below. The stadia constant for the optical level is K = 100. a. Assume that the sight is horizontal. b. Assume that the sight is inclined 15⁰ from the horizontal. E₂ 20 19-
- S3. 25 mm 25 mm Cross-sectional area of the beam given inthe figure a acording to the axis 100 mm Find the moment of inartia th = 40 mm). 125 mm -75 mm- -75 mm- 150 mm! 30 mm 100 mm a 25 mmDetermine the moment of inertia of the shaded area with respect ot the x-axis. Where b=21inch and h=17inchDetermine the distance H from the upper surface of the symmetric double-T beam cross section to the location of the centroid. 240 ….. 14 +50 155 14 Dimensions in millimeters A) 53.5 mm B) 54.6 mm C) 51.7 mm (D) 52.5 mm H