Dim ar() As String = {"vb", "java", "C++"} %3D MsgBox(ar(2).Length & ar(1).Insert(2, "2")) O Error--out of bound O 3ja2va O 2ja2va O none
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- a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?40.|Asiacell docs.google.com/forms :D yuustivi بل اجابة هذا السؤال بشكل PDF Describe the difference between tl .following two progran class Progarml { public static void main(String[] args) { int[] a = {1, 2}: q3(a); System.out.println( a[0]+ " " +a[1]);} class Program2 { public static void main(String[] args) { int[] a = {1, 2}; q3(a[0], a[ 1]); System.out.println(a[0]+ " "+ a[1]);} static void swap(int[] a) { int t = a[0]: a[0] = a[1]: a[1] = t:} static void q3(int n1, int n2) { int t =n1; nl = n2; n2 = t;} إضافة ملف 4 صفحة 3 من التالي Es ل كلمات المرور عبر نماذج Google مطلقًا.#include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…
- C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".Find errors in this code also: internalstatdchkPalindrome(string str) { for(int i = 0, j = str.Length - 1; i < str.Length / 2; i++, j--) { if(str[i] != str[j]) { flag = false; break; } } if(flag) { ome"); } else Console.ine("Not Palindrome"); }Implement the following function which accepts a string as parameter and reverses it, without using any function from the string library. void strReverse(char *str)
- In c++ Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, th backwards End each loop with a newline. Ex If courseGrades (7, 9, 11, 10), print: 7 9 11 10 10 11 9 7 Hint Use two for loops. Second loop starts with i=NUM VALS-1. (Notes) Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades(4) See 'How to Use zyBooks Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message 32344345730rity? 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 const int NUM VALS-4; int courseGrades [NUM VALS]; int i; for (i = 0; i > courseGrades[1]; } y Your solution goes here YTAKE A LIST OF STRING FROM THE USER AND COUNT THE NUMBER OF UNIQUE ELEMENTS WITHOUT USING THE FOR, WHILE, Do-WHILE LOOPS. PREFERRED PROGRAMMING LANGUAGE: JAVA/C++def strPattern(mystr):lenght = len(mystr)mystr1 = ""for i in range(lenght - 1):mystr1 = mystr1 + mystr[i].upper() + str(i + 1)if lenght == 0:return mystr1return mystr1 + mystr[-1].upper()s = input("enter a word: ")print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line HOW CAN I FIX THIS QUESTION?
- Determine the growth function and order of the following codefragment:for (int count=0; count < n; count++){ for (int count2=0; count2 < n; count2=count2+2) { System.out.println(count + ", " + count2); }}1. In C++, Displaying the elements of array using while loop?public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…