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- please code in pythonis_phone_num: This Boolean function takes a string and returns True if it is in the formatddd-ddd-dddd, where d is a digit, False otherwise. Example calls:is_phone_num('123-456-7890') --> Trueis_phone_num('123-4556-7890') --> Falseis_phone_num('(123)456-7890') --> Falsewaht is value versionFor each expression in the left-hand column, indicate its value in the right-hand column. Be sure to list a constant of appropriate type (e.g., 7.0 rather than 7 for a double, Strings in "quotes"). Expression Value (int) 9.0/2 23 % 5 - (16 % 10) 1.5 * 2 - 6 / 4 “1”+1 (2+3)+”Hello”+4+2*3 23456/100%10 “a”+4-2
- #include <stdio.h>#include <stdlib.h> //declaring variables globally to calculate coinsint cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //calculate change//pass change variable by addressvoid calculateChange(int* change) {//calculate change only if change is positiveif(*change > 0) {if(*change >= 50) {*change -= 50;cent50++;}else if(*change >= 20) {*change -= 20;cent20++;}else if(*change >= 10) {*change -= 10;cent10++;}else if(*change >= 05) {*change -= 05;cent05++;}//call calculateChange recursively calculateChange(change);}} // function to display the cents valuesvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50);if(cent20)printf("\n20 Cents : %d coins", cent20);if(cent10)printf("\n10 Cents : %d coins", cent10);if(cent05)printf("\n05 Cents : %d coins", cent05);//reset all cent variables with 0cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //take change input from user//change variable passed addressvoid TakeChange(int*…2.15 LAB: Musical note frequencies On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved as follows:print(f'{your_value1:.2f} {your_value2:.2f} {your_value3:.2f} {your_value4:.2f} {your_value5:.2f}')______ does not end a request. response.write() response.end() response.render()
- given input word, return the list of abbreviations.ex)word => ['word', 'wor1', 'wo1d', 'wo2', 'w1rd', 'w1r1', 'w2d', 'w3', '1ord', '1or1', '1o1d', '1o2', '2rd', '2r1', '3d', '4']""" def generate_abbreviations(word): def backtrack(result, word, pos, count, cur): if pos == len(word): if count > 0: cur += str(count) result.append(cur) return if count > 0: # add the current word backtrack(result, word, pos+1, 0, cur+str(count)+word[pos]) else: backtrack(result, word, pos+1, 0, cur+word[pos]) # skip the current word backtrack(result, word, pos+1, count+1, cur).most_frequent_word() takes a string as the input parameter and returns two values; the word that appears most frequently in that string and the total number of times that word appears in that string. In case of a tie, return the first word that appears in the string. Hint: you can use the unique_words function that you wrote in (4). Sample outputs:>>> data = “chapter one hottest day summer so far drawing close drowsy silence lay over large square houses privet drive cars usually gleaming stood dusty drives lawns once emerald green lay parched yellowing”>>> word = most_frequent_word(data)>>> print(word)('lay', 2)>>> data_2 = "a cat in a hat and a big black bear on a big black rug">>> word = most_frequent_word(data_2)>>> print(word)('a', 4)Fix the following code:Dim dblRegularPay As DoubleDim dblOvertimePay As DoubleintRegularPay = 783.87intOvertimePay = 105.92lbl.TotalPay = (dblRegularPay + dblOvertimePay).ToString ('C')
- #include <iostream> using namespace std; int main() { string c_name ; string car_n; int n, member_n , total ,d; char choice; cout<< "Muscat Auto Workshop"<<endl<<endl; cout<< "Enter customer name : ";cin>>c_name; cout<<" Enter car plate number : ";cin>>car_n; cout<<" choice the required service "<<endl; cout<<" 1-Basic Tuning : 50 OMR "<<endl; cout<<" 2-Software Re-installation : 60 OMR "<<endl; cout<<" 3-Parts Replacement : 100 OMR"<<endl; cout<<" 4-Body Paint : 120 OMR"<<endl; cin>>n; if(n==1) { cout<<" charges before discout = 50 OMR "<<endl; } else if ( n==2) { cout <<" charges before discount = 60 OMR "<<endl; }else if (n==3) { cout<<" charges before discount = 100 OMR "<<endl; }else if (n==4 ) { cout<<" charges before discount = 120 OMR"<<endl; } cout<<" Do you…To remove the value of a variable but keeping the variable in PowerShell, we can use this cmdlet: Group of answer choices Delete-Value Clear-Variable Clear-Value Remove-Variableprogramming: C# (Csharp) Help me please kindly apply the C# METHOD on my program Here is my code: using System; //HEADERclass program { static void Main() { int n; Console.WriteLine("Enter 5-digit number: "); // PROMPT USER n = Convert.ToInt32(Console.ReadLine()); // SCAN Console.Write(n / 10000 % 10 + "*"); Console.Write(n / 1000 % 10 + "*"); //ASTERISK PROCESS PART Console.Write(n / 100 % 10 + "*"); Console.Write(n / 10 % 10 + "*"); Console.Write(n % 10 ); // RESULT }}