Each step in the following process has a yield of 80.0%. CH, +4CL, + CCI, + 4HCH CCI, +2 HF =→ CCL,E, + 2HCI The CCI, formed in the first step is used as a reactant in the second step. #5.50 mol CH, reacts, what is the total amount of HCl produced? Assume that CI, and HF are present in excess. mol moles HCE:

Chemistry: Matter and Change
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ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter11: Stoichiometry
Section: Chapter Questions
Problem 63A
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Each step in the following process has a yield of 80.0%.
CIL, +4C1,
CCI, +4 HCH
CCI, +2HF
CCL, E, + 2 HCİ
The CCI, formed in the first step is used as a reactant in the second step.
If 5.50 mol CH, reacts, what is the total amount of HOCI produced? Assume that Cl, and HF are present in excess.
moles HCE:
mol
Transcribed Image Text:Each step in the following process has a yield of 80.0%. CIL, +4C1, CCI, +4 HCH CCI, +2HF CCL, E, + 2 HCİ The CCI, formed in the first step is used as a reactant in the second step. If 5.50 mol CH, reacts, what is the total amount of HOCI produced? Assume that Cl, and HF are present in excess. moles HCE: mol
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