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Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults woul expensive.) Assume adults have hip widths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.9 in. Find P99. That smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults woul expensive.) Assume adults have hip widths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.9 in. Find P99. That smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults would require very wide seats that would be much too expensive.) Assume adults have hip widths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.9 in. Find P99. That is, find the hip width for adults that separates the smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)
Transcribed Image Text:Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults would require very wide seats that would be much too expensive.) Assume adults have hip widths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.9 in. Find P99. That is, find the hip width for adults that separates the smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)
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